下面问题除了空指针，还有没有其他错误，怎么改

错误：
HTTP Status 500 -

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type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:510)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:393)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

java.lang.NullPointerException
com.zk.SplitPage.initialize(SplitPage.java:14)
org.apache.jsp.search_005ffriend_005fresult_jsp._jspService(search_005ffriend_005fresult_jsp.java:101)，，//我的101行是：
SplitPage.initialize(rs,10);这个问题是不是解决了空指针就没事了？
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:332)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

note The full stack trace of the root cause is available in the Apache Tomcat/5.5.17 logs.

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Apache Tomcat/5.5.17

SplitPage.initialize方法的构建：
public void initialize(ResultSet rs,int pageSize)
   {this.pageSize=pageSize;
    try
      {this.rs=rs;
       this.rsmd=this.rs.getMetaData();
       if(this.rs!=null)
         {this.rs.last();
          this.rowCount=this.rs.getRow();
          this.rs.first();
          this.PageCount=(this.rowCount-1)/this.pageSize+1;
         }
       else
        this.rowCount=0;
      }
    catch(SQLException e)
      {System.out.println(e.toString());
      }
   }

7 个解决方案

#1

怎么没人解？

#2

SplitPage.java:14

应该是第14行的问题！

#3

13:this.rs=rs;
14: this.rsmd=this.rs.getMetaData();
15: if(this.rs!=null)

#4

你的 rs 肯的定是 null 的。
你在你传入的参数那里调试。
错误没有在这里。是你传入的 ResultSet 为 null

#5

if(this.rs!=null)
{this.rs.last();
或许rs不是null而是没有next

#6

public void initialize(ResultSet rs,int pageSize)
   {this.pageSize=pageSize;
    try
      {
if(rs!=null){
this.rs=rs;
       this.rsmd=this.rs.getMetaData();
       if(this.rs!=null)
         {this.rs.last();
          this.rowCount=this.rs.getRow();
          this.rs.first();
          this.PageCount=(this.rowCount-1)/this.pageSize+1;
         }
       else
        this.rowCount=0;
      } }
    catch(SQLException e)
      {System.out.println(e.toString());
      }
   }

#7

就是说rs.next()为空你可以这样写if(this.rs.next()!=null)

#1