期望嵌套的XML结构但接收SOAP结构

I'm making an app that is requesting data from a Web Service (implementing Soap).

我正在创建一个从Web服务请求数据的应用程序（实现Soap）。

People who are viewing this pleaase post doubts in comments... I havent got any response to the question do ask me if there is any doubts, i really need help, am stuck!!

正在观看这个请求的人在评论中表示怀疑......我没有得到任何回答问题请问我是否有任何疑问，我真的需要帮助，我被困！

So to make request I have to use ksoap libraries.. the Web service is coded to return a response of type XML. When the web service itself is tested on a browser it displays a result which is as follows:

因此，为了发出请求，我必须使用ksoap库.Web服务被编码为返回XML类型的响应。在浏览器上测试Web服务本身时，它会显示如下结果：

?xml version="1.0" encoding="utf-8" ?> 
- <SOBKeyList>
- <Key>
  <value>12686</value> 
  </Key>
- <Key>
  <value>16238</value> 
  </Key>
- <Key>
  <value>26978</value> 
  </Key>
  </SOBKeyList>

clearly an XML file...

显然是一个XML文件......

However when i use ths code to get a result:

但是，当我使用该代码获得结果时：

    public String getXmlFromUrl(String url) {
    // TODO Auto-generated method stub
    String xml = null;
    SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
    PropertyInfo pi = new PropertyInfo();

    pi.setName("fkey");
    pi.setValue(0);
    pi.setType(Integer.class);
    request.addProperty(pi);

    pi = new PropertyInfo();

    pi.setName("tkey");
    pi.setValue(999999);
    pi.setType(Integer.class);
    request.addProperty(pi);


    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
            SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);
    HttpTransportSE httpTransport = new HttpTransportSE(url);
    Object response = null; 

    try {
        httpTransport.call(SOAP_ACTION, envelope);
        response = envelope.getResponse();
        xml = response.toString();
        Log.d("xml:", xml);
    } catch (SoapFault e) {
        // TODO Auto-generated catch block
        Log.d("Soap Fault", e.toString());
    } catch (IOException e) {
        // TODO Auto-generated catch block
        Log.d("IOexception", e.toString());
    } catch (XmlPullParserException e) {
        // TODO Auto-generated catch block
        Log.d("XmlPullParserException", e.toString());
    }

    return xml;
}

It returns a nested SOAP structure confirmed by the Log entry which i make ( Log.d("xml:", xml); ) The corresponding LogCat entry is: (i've formatted it to make it the SOAP structure's heirarchy apparent... )

它返回一个由我生成的Log条目确认的嵌套SOAP结构（Log.d（“xml：”，xml）;）相应的LogCat条目是:(我已将其格式化为使其成为SOAP结构的层次结构明显... 。）

anyType{
      SOBKeyList=anyType{
                          Key=anyType{value=12686 ; };
                          Key=anyType{value=16238 ; };
                          Key=anyType{value=26978 ; };
                         };
          }

The reason why i necessarily need an XML is because later I parse the string to get a DOM element and when the above string is passed it returns the following:

我之所以需要XML的原因是因为后来我解析字符串以获取DOM元素，并且当传递上述字符串时，它返回以下内容：

org.xml.sax.SAXParseException: Unexpected token (position:TEXT anyType{SOBKeyLi...@1:119 in java.io.StringReader@40ec9c68)

org.xml.sax.SAXParseException：意外的标记（位置：TEXT anyType {SOBKeyLi ... java.io.StringReader@40ec9c68中的@ 1：119）

also from there onward my entire code depends on the fact that the response was XML.

从那时起我的整个代码依赖于响应是XML的事实。

Explaination of the reason why i expected an XML : Now you may asked why I coded my app expecting XML when i had not tested the Web service the reason is: The Web service was coded my a third party who assured me of an XML response , now i dont have enough time to change my remaining code to exploit a SOAP structure !! -_- I'm in a fix. Please help!

解释为什么我期望XML的原因：现在你可能会问我为什么在没有测试Web服务的情况下编写我的应用程序期望XML的原因是：Web服务编码我的第三方谁向我保证XML响应，现在我没有足够的时间来改变我的剩余代码来利用SOAP结构！ -_-我正在解决问题。请帮忙！

1 个解决方案

#1

Try this:

尝试这个：

String responseXML = httpTransport.responseDump;

HttpTransportSE.responseDump gives you response in XML format.
HttpTransportSE.responseDump以XML格式为您提供响应。
HttpTransportSE.requestDump gives you request in XML format.
HttpTransportSE.requestDump以XML格式提供请求。

However to be able to change and retrieve any of these values you must set the debug field of HttpTransportSE to true so your code should look like...

但是，为了能够更改和检索这些值中的任何一个，您必须将HttpTransportSE的调试字段设置为true，以便您的代码看起来像......

    HttpTransportSE httpTransport = new HttpTransportSE(url);
    httpTransport.debug =true;      
    try {
        httpTransport.call(SOAP_ACTION, envelope);          
        xml = httpTransport.responseDump;
        Log.d("xml:", "is:" + xml);     
    }

Also you can parse your response like as follow:

您也可以解析您的回复，如下所示：

ArrayList<String> listValues = new ArrayList<String>();

            httpTransport.call(SOAP_ACTION, envelope);
            SoapObject response = (SoapObject) envelope.getResponse();

            SoapObject soapSOBKeyList = (SoapObject) response.getProperty("SOBKeyList");

            int keyCount = soapSOBKeyList.getPropertyCount();

            for (int i = 0; i < keyCount; i++) {
                String value = soapSOBKeyList.getPropertyAsString(i);
                listValues.add(value);
            }

            return listValues;

#1