I have a list of lists (can't be tuples since I have to generate it dynamically) and it is structured as a list of lists of one int and one float Like so:
我有一个列表列表列表(不能是元组，因为我必须动态生成它)，它的结构是由一个int和一个float的列表组成的列表，如下所示:
[[1,1.0345],[2,5.098],[3,4.89],[2,5.97]]
I want to get it sorted but I have only managed to get the built in sorting function to sort it by the first element of the lists or not do anything, but I need to sort them by the second element of the list and I don't want to implement my own sorting function. So an example of what I would want is:
我想把它分类,但我只有设法让建成的排序函数,它的第一个元素列表或不做任何事,但我需要第二个元素排序的列表,我不想实现自己的排序功能。我想要的一个例子是
[[1,1.0345],[3,4.89],[2,5.098],[2,5.97]]
Could someone tell me how to get one of the built in sorting functions to do this?
有人能告诉我如何让一个内置的排序函数来做这个吗?
3 个解决方案
#1
18
Pass the key argument.
通过参数的关键。
L.sort(key=operator.itemgetter(1))
#2
11
>>> l = [[1,1.0345],[2,5.098],[3,4.89],[2,5.97]]
>>> l.sort(key=lambda x: x[1])
>>> l
[[1, 1.0345], [3, 4.8899999999999997], [2, 5.0979999999999999], [2, 5.9699999999999998]]
#3
3
How about using they key parameter of sorted...
使用它们排序的关键参数……
sorted_list = sorted([[1,1.0345],[3,4.89],[2,5.098],[2,5.97]], key=lambda x: x[1])
This tells python to sort the list of lists using the item at index 1 of each list as the key for the compare.
这告诉python在每个列表的索引1中使用条目排序列表，作为比较的键。
#1
18
Pass the key argument.
通过参数的关键。
L.sort(key=operator.itemgetter(1))
#2
11
>>> l = [[1,1.0345],[2,5.098],[3,4.89],[2,5.97]]
>>> l.sort(key=lambda x: x[1])
>>> l
[[1, 1.0345], [3, 4.8899999999999997], [2, 5.0979999999999999], [2, 5.9699999999999998]]
#3
3
How about using they key parameter of sorted...
使用它们排序的关键参数……
sorted_list = sorted([[1,1.0345],[3,4.89],[2,5.098],[2,5.97]], key=lambda x: x[1])
This tells python to sort the list of lists using the item at index 1 of each list as the key for the compare.
这告诉python在每个列表的索引1中使用条目排序列表，作为比较的键。