Ruby将两个阵列合并为一个

Here is my situation. I have 2 Arrays

这是我的情况。我有2个阵列

@names = ["Tom", "Harry", "John"]

@emails = ["[e-mail]", "[e-mail]", "[e-mail]"]

I want to combine these two into some Array/Hash called @list so I can then iterate in my view something like this:

我想将这两个组合成一些名为@list的Array / Hash，这样我就可以在我的视图中迭代这样的东西：

<% @list.each do |item| %>
<%= item.name %><br>
<%= item.email %><br>
<% end %>

I'm having trouble understanding how I can achieve this goal. Any thoughts?

我无法理解如何实现这一目标。有什么想法吗？

5 个解决方案

#1

@names  = ["Tom", "Harry", "John"]
@emails = ["[e-mail]", "[e-mail]", "[e-mail]"]

@list = @names.zip( @emails )
#=> [["Tom", "[e-mail]"], ["Harry", "[e-mail]"], ["John", "[e-mail]"]]

@list.each do |name,email|
  # When a block is passed an array you can automatically "destructure"
  # the array parts into named variables. Yay for Ruby!
  p "#{name} <#{email}>"
end
#=> "Tom <[e-mail]>"
#=> "Harry <[e-mail]>"
#=> "John <[e-mail]>"

@urls = ["yahoo.com", "ebay.com", "google.com"]

# Zipping multiple arrays together
@names.zip( @emails, @urls ).each do |name,email,url|
  p "#{name} <#{email}> :: #{url}"
end
#=> "Tom <[e-mail]> :: yahoo.com"
#=> "Harry <[e-mail]> :: ebay.com"
#=> "John <[e-mail]> :: google.com"

#2

Just to be different:

只是为了与众不同：

[@names, @emails, @urls].transpose.each do |name, email, url|
  # . . .
end

This is similar to what Array#zip does except that in this case there won't be any nil padding of short rows; if something is missing an exception will be raised.

这类似于Array＃zip所做的，除了在这种情况下不会有任何短行的nil填充;如果缺少某些东西，将引发异常。

#3

Hash[*names.zip(emails).flatten]

This will give you a hash with name => email.

这将为您提供名称=>电子邮件的哈希。

#4

You can use zip to zip together the two arrays and then map to create Item objects from the name-email-pairs. Assuming you have an Item class whose initialize methods accepts a hash, the code would look like this:

您可以使用zip将两个数组压缩在一起，然后映射以从名称 - 电子邮件对创建Item对象。假设你有一个其初始化方法接受哈希的Item类，代码如下所示：

@list = @names.zip(@emails).map do |name, email|
  Item.new(:name => name, :email => email)
end

#5

Try This

尝试这个

Hash[@names.zip(@emails)]

You have two arrays @names = ["Tom", "Harry", "John"]

你有两个数组@names = [“Tom”，“Harry”，“John”]

@emails = ["[e-mail]", "[e-mail]", "[e-mail]"]

@emails = [“[e-mail]”，“h @ gmail.com”，“j @ gmail.com”]

@names.zip(@emails) it merge @emails to the @names associated with their index like below [["Tom", "[e-mail]"], ["Harry", "[e-mail]"], ["John", "[e-mail]"]]

@ names.zip（@emails）它将@emails合并到与他们的索引关联的@names，如下面[[“Tom”，“[e-mail]”]，[“Harry”，“h @ gmail.com”] ，[“John”，“j @ gmail.com”]]

Now we can convert this array into hash using Hash[@names.zip(@emails)]

现在我们可以使用Hash [@ names.zip（@emails）]将此数组转换为哈希