一、题目
There are two sorted arrays nums1 and nums2 of size m and n respectively.
Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).
Example 1:
nums1 = [1, 3]
nums2 = [2]
The median is 2.0
Example 2:
nums1 = [1, 2]
nums2 = [3, 4]
The median is (2 + 3)/2 = 2.5
二、代码
简单合并,排序,取中值
class Solution {
public:
double findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2) {
int *it;
int m = nums1.size()?nums1.size():0;
int n = nums2.size()?nums2.size():0;
int *merge = new int[m+n];
if(!nums1.empty()){
it = &*nums1.begin();
memcpy(merge,it,sizeof(int)*m);
}
if(!nums2.empty()){
it = &*nums2.begin();
memcpy(merge+m,it,sizeof(int)*n);
}
sort(merge,merge+m+n);
//注意数组下标和计算的下标区别
return (m+n)%2?1.0*merge[(m+n)>>1]:(merge[(m+n-1)>>1]+merge[(m+n)>>1])/2.0;
}
};