I have two arrays one is fix to be 8 letters and the other depends on the user. I have to take user input and put in an array (done) but I need to check if the users input (it is a word) letters are in the other array ? how can I do it ?
我有两个数组一个是固定的8个字母,另一个取决于用户。我必须接受用户输入并放入一个数组(完成),但是我需要检查用户输入(它是一个单词)的字母是否在另一个数组中?我怎么做呢?
1 个解决方案
#1
4
You can use Perl's (v5.10+) smartmatch operator ~~
to check if a string is an element of an array. The matching is case-sensitive:
您可以使用Perl的(v5.10+) smartmatch操作符~~来检查字符串是否是数组的元素。是区分大小写的匹配:
use strict;
use warnings;
my @words = map lc, qw/This is a test/;
print 'Enter a word: ';
chomp( my $entry = <> );
print qq{The word "$entry" is}
. ( lc $entry ~~ @words ? '' : ' not' )
. ' in @words.'
Sample run:
示例运行:
Enter a word: This
The word "This" is in @words.
#1
4
You can use Perl's (v5.10+) smartmatch operator ~~
to check if a string is an element of an array. The matching is case-sensitive:
您可以使用Perl的(v5.10+) smartmatch操作符~~来检查字符串是否是数组的元素。是区分大小写的匹配:
use strict;
use warnings;
my @words = map lc, qw/This is a test/;
print 'Enter a word: ';
chomp( my $entry = <> );
print qq{The word "$entry" is}
. ( lc $entry ~~ @words ? '' : ' not' )
. ' in @words.'
Sample run:
示例运行:
Enter a word: This
The word "This" is in @words.