Case 3 is an option to add a book to the structure. As long as books with titles without spaces are added, they are ok, whenever I try to put a name that has a space in it, the compiler goes crazy, sorta like what it would do if you execute an infinite loop. Why and what is the solution?
案例3是向结构添加书籍的选项。只要添加没有空格的书籍,它们就可以了,每当我尝试放入一个有空格的名称时,编译器就会变得疯狂,就像执行无限循环一样。为什么以及解决方案是什么?
struct bookStruct
{
string bookTitle;
int bookPageN;
int bookReview;
float bookPrice;
};
const int MAX_BOOKS=10;
case 3:
{
for(int i=0;i<MAX_BOOKS;i++)
{
if(books[i].bookTitle=="\0")
{
cout << "\nPlease Enter the Title: ";
cin >> books[i].bookTitle ;
cout << "\nPlease Enter Total Number of Pages: ";
cin >> books[i].bookPageN ;
cout << "\nPlease Enter Rating (stars): ";
cin >> books[i].bookReview ;
cout << "\nPlease Enter Price: ";
cin >> books[i].bookPrice;
cout << "\n\nBook Added.\n\n";
break;
}
}break;
}
1 个解决方案
#1
4
The input operator >> stops at space when reading strings.
What you want to use is std::getline.
输入操作符>>在读取字符串时停止在空格处。你想要使用的是std :: getline。
cout << "\nPlease Enter the Title: ";
std::getline(std::cin, books[i].bookTitle);
The input operator >> when reading a number will also stop at a space or newline (leaving them on the input stream). Thus when you wrap around to the next book there is still a '\n' character on the input stream. So for numbers you also need to use std::getline(). But in this case you need to convert the value to an integer.
读取数字时的输入操作符>>也将停留在空格或换行符处(将它们留在输入流上)。因此,当你回到下一本书时,输入流上仍然有一个'\ n'字符。因此对于数字,您还需要使用std :: getline()。但在这种情况下,您需要将值转换为整数。
cout << "\nPlease Enter Total Number of Pages: ";
std::string line;
std::getline(std::cin, line);
std::stringstream linestream(line);
linestream >> books[i].bookPageN ;
#1
4
The input operator >> stops at space when reading strings.
What you want to use is std::getline.
输入操作符>>在读取字符串时停止在空格处。你想要使用的是std :: getline。
cout << "\nPlease Enter the Title: ";
std::getline(std::cin, books[i].bookTitle);
The input operator >> when reading a number will also stop at a space or newline (leaving them on the input stream). Thus when you wrap around to the next book there is still a '\n' character on the input stream. So for numbers you also need to use std::getline(). But in this case you need to convert the value to an integer.
读取数字时的输入操作符>>也将停留在空格或换行符处(将它们留在输入流上)。因此,当你回到下一本书时,输入流上仍然有一个'\ n'字符。因此对于数字,您还需要使用std :: getline()。但在这种情况下,您需要将值转换为整数。
cout << "\nPlease Enter Total Number of Pages: ";
std::string line;
std::getline(std::cin, line);
std::stringstream linestream(line);
linestream >> books[i].bookPageN ;