Its been a while since I've used arrays in Excel VBA so please forgive me...
我在Excel VBA中使用数组已经有一段时间了,请原谅我……
I'm trying to define a dynamic array based consecutive matching cells that are determined in a loop. I'm sure my syntax is wrong for defining the arrays I'm just not sure how. The difficulty is that my array consists of about 6 consecutive rows in 1 column, plus another cell in a different column. Any ideas?
我正在尝试定义一个基于动态数组的连续匹配单元格,它们是在循环中确定的。我确定我的语法定义数组是错误的,只是我不知道如何定义。难点在于,我的数组由一个列中大约6个连续的行,加上另一个列中的单元格。什么好主意吗?
Sub calib_range()
Dim instrument As Variant
Dim calibrator As Variant
Dim lastrow As Integer
lastrow = ThisWorkbook.ActiveSheet.Range("b2").SpecialCells(xlCellTypeLastCell).Row
For i = 4 To lastrow
If Cells(i, 4) Like "MPC*" Then
'enter loop to determine length of MPC* array
For x = i + 1 To lastrow
If Cells(x, 4) = Cells(x - 1, 4) Then
Else
x = x - 1
Exit For
End If
Next x
instrument = Array(Cells(i, 17), Range(Cells(i, 14), Cells(x, 14)))
calibrator = Array(0, Range(Cells(i, 12), Cells(x, 12)))
Slope = Application.WorksheetFunction.Slope(instrument, calibrator)
Intercept = Application.WorksheetFunction.Intercept(instrument, calibrator)
Cells(i, 22) = Slope
Cells(i, 23) = Intercept
End If
Next i
End Sub
1 个解决方案
#1
1
Your problem is here:
你的问题是:
calibrator = Array(0, Range(Cells(i, 12), Cells(x, 12)))
You are not allowed to do so, because VBA thinks that in your array you get a 0 and a range. Thus, your array consists of two different types of valuse. Which is not what you need.
不允许这样做,因为VBA认为在数组中会有一个0和一个范围。因此,数组由两种不同类型的valuse组成。这不是你需要的。
Read here a little more about how to initialize arrays, it is well explained.
在这里再多读一些关于如何初始化数组的内容,会得到很好的解释。
Edit: Also on the previous line you simply make an array of ranges. What would work out for you is probably something like this:
编辑:在前一行中,你只需要创建一个范围数组。对你来说可能是这样的:
Public Sub CheckArray()
Dim my_array() As Double
ReDim my_array(6)
my_array(0) = Cells(1, 17)
my_array(1) = Cells(2, 17)
my_array(2) = Cells(3, 17)
my_array(3) = Cells(4, 17)
my_array(4) = Cells(5, 17)
my_array(5) = Cells(6, 17)
my_array(6) = Cells(7, 17)
End Sub
#1
1
Your problem is here:
你的问题是:
calibrator = Array(0, Range(Cells(i, 12), Cells(x, 12)))
You are not allowed to do so, because VBA thinks that in your array you get a 0 and a range. Thus, your array consists of two different types of valuse. Which is not what you need.
不允许这样做,因为VBA认为在数组中会有一个0和一个范围。因此,数组由两种不同类型的valuse组成。这不是你需要的。
Read here a little more about how to initialize arrays, it is well explained.
在这里再多读一些关于如何初始化数组的内容,会得到很好的解释。
Edit: Also on the previous line you simply make an array of ranges. What would work out for you is probably something like this:
编辑:在前一行中,你只需要创建一个范围数组。对你来说可能是这样的:
Public Sub CheckArray()
Dim my_array() As Double
ReDim my_array(6)
my_array(0) = Cells(1, 17)
my_array(1) = Cells(2, 17)
my_array(2) = Cells(3, 17)
my_array(3) = Cells(4, 17)
my_array(4) = Cells(5, 17)
my_array(5) = Cells(6, 17)
my_array(6) = Cells(7, 17)
End Sub