查找目录中的文件复制到新文件名

Want to copy the files which has 63 in its name , change it to 64 and copy it in the same directory. How can i do it.

要复制名称中包含63的文件，将其更改为64并将其复制到同一目录中。我该怎么做。

Tried using awk,sed not working.

尝试使用awk，sed不工作。

ls *63*

For example if the file is test63.txt it should get copied to test64.txt in the same directory . if the file is 63test.txt it should get copied to 64text.txt

例如，如果文件是test63.txt，它应该被复制到同一目录中的test64.txt。如果文件是63test.txt，它应该被复制到64text.txt

2 个解决方案

#1

What about something like this:

这样的事情怎么样：

for f in *63*; do newname=`echo $f | sed 's/63/64/'`; cp $f $newname; done

Broken down into multiple lines:

细分为多行：

for f in *63*; do
  newname=`echo $f | sed 's/63/64/'`
  cp $f $newname
done

#2

A generalized bash solution with a specifiable number that is incremented by 1:

一个广义的bash解决方案，其可指定的数字递增1：

n=63
for f in *"$n"*; do
  cp "$f" "${f/$n/$((n+1))}"
done

#1