I have a Directory(Linux/Unix) on a Apache Server with a lot of subdirectory containing lot of files like this:
我在Apache服务器上有一个目录(Linux / Unix),其中有很多子目录,包含很多这样的文件:
- Dir - 2010_01/ - 142_78596_101_322.pdf - 12_10.pdf - ... - 2010_02/ - ...
How can i find all files with filesnames looking like: *_*_*_*.pdf
? where * is always a digit!!
我怎样才能找到文件名看起来像的所有文件:* _ * _ * _ * .pdf?其中*总是一个数字!!
I try to solve it like this:
我试着像这样解决它:
ls -1Rl 2010-01 | grep -i '\(\d)+[_](\d)+[_](\d)+[_](\d)+[.](pdf)$' | wc -l
But the regular expression \(\d)+[_](\d)+[_](\d)+[_](\d)+[.](pdf)$
doesn't work with grep.
但正则表达式\(\ d)+ [_](\ d)+ [_](\ d)+ [_](\ d)+ [。](pdf)$不适用于grep。
Edit 1: Trying ls -l 2010-03 | grep -E '(\d+_){3}\d+\.pdf' | wc -l
for example just return null. So it's dont work perfectly
编辑1:尝试ls -l 2010-03 | grep -E'(\ d + _){3} \ d + \ .pdf'| wc -l例如只返回null。所以它不能完美地运作
3 个解决方案
#1
3
Try using find
.
尝试使用find。
The command that satisfies your specification __*_*.pdf where * is always a digit
:
满足您的规范的命令__ * _ * .pdf其中*始终为数字:
find 2010_10/ -regex '__\d+_\d+\.pdf'
You seem to be wanting a sequence of 4 numbers separated by underscores, however, based on the regex that you tried.
您似乎想要一个由下划线分隔的4个数字的序列,但是,基于您尝试的正则表达式。
(\d+_){3}\d+\.pdf
Or do you want to match all names containing solely numbers/underscores?
或者您想匹配仅包含数字/下划线的所有名称?
[\d_]+\.pdf
#2
1
First, you should be using egrep vs grep or call grep with -E for extended patterns.
首先,您应该使用egrep vs grep或使用-E调用grep来扩展模式。
So this works for me:
所以这对我有用:
$ cat test2.txt
- Dir
- 2010_01/
- 142_78596_101_322.pdf
- 12_10.pdf
- ...
- 2010_02/
- ...
Now egrep that file:
现在egrep那个文件:
cat test2.txt | egrep '((?:\d+_){3}(?:\d+)\.pdf$)'
- 142_78596_101_322.pdf
Since there are parenthesis around the whole pattern, the entire file name will be captured.
由于整个模式周围有括号,因此将捕获整个文件名。
Note that the pattern does NOT work with grep in traditional mode:
请注意,在传统模式下,模式不适用于grep:
$ cat test2.txt | grep '((?:\d+_){3}(?:\d+)\.pdf$)'
... no return
But DOES work if you use the extend pattern switch (the same as calling egrep):
但是,如果使用扩展模式开关(与调用egrep相同),则可以工作:
$ cat test2.txt | grep -E '((?:\d+_){3}(?:\d+)\.pdf$)'
- 142_78596_101_322.pdf
#3
0
Thanks to gbchaosmaster and the wolf I find a way which work for me:
感谢gbchaosmaster和狼我找到了适合我的方法:
Into a Directory:
进入目录:
find . | grep -P "(\d+_){3}\d+\.pdf" | wc -l
At the Root Directory:
在根目录:
find 20*/ | grep -P "(\d+_){3}\d+\.pdf" | wc -l
#1
3
Try using find
.
尝试使用find。
The command that satisfies your specification __*_*.pdf where * is always a digit
:
满足您的规范的命令__ * _ * .pdf其中*始终为数字:
find 2010_10/ -regex '__\d+_\d+\.pdf'
You seem to be wanting a sequence of 4 numbers separated by underscores, however, based on the regex that you tried.
您似乎想要一个由下划线分隔的4个数字的序列,但是,基于您尝试的正则表达式。
(\d+_){3}\d+\.pdf
Or do you want to match all names containing solely numbers/underscores?
或者您想匹配仅包含数字/下划线的所有名称?
[\d_]+\.pdf
#2
1
First, you should be using egrep vs grep or call grep with -E for extended patterns.
首先,您应该使用egrep vs grep或使用-E调用grep来扩展模式。
So this works for me:
所以这对我有用:
$ cat test2.txt
- Dir
- 2010_01/
- 142_78596_101_322.pdf
- 12_10.pdf
- ...
- 2010_02/
- ...
Now egrep that file:
现在egrep那个文件:
cat test2.txt | egrep '((?:\d+_){3}(?:\d+)\.pdf$)'
- 142_78596_101_322.pdf
Since there are parenthesis around the whole pattern, the entire file name will be captured.
由于整个模式周围有括号,因此将捕获整个文件名。
Note that the pattern does NOT work with grep in traditional mode:
请注意,在传统模式下,模式不适用于grep:
$ cat test2.txt | grep '((?:\d+_){3}(?:\d+)\.pdf$)'
... no return
But DOES work if you use the extend pattern switch (the same as calling egrep):
但是,如果使用扩展模式开关(与调用egrep相同),则可以工作:
$ cat test2.txt | grep -E '((?:\d+_){3}(?:\d+)\.pdf$)'
- 142_78596_101_322.pdf
#3
0
Thanks to gbchaosmaster and the wolf I find a way which work for me:
感谢gbchaosmaster和狼我找到了适合我的方法:
Into a Directory:
进入目录:
find . | grep -P "(\d+_){3}\d+\.pdf" | wc -l
At the Root Directory:
在根目录:
find 20*/ | grep -P "(\d+_){3}\d+\.pdf" | wc -l