如何从另一个脚本运行我的脚本并等待完成？

I need to call a script called build_report.php, pass in a URL variable named partno and wait until it is finished before continuing.

我需要调用一个名为build_report.php的脚本,传入一个名为partno的URL变量,并等到它完成后再继续。

This script builds a report and then an email is sent out to our customer so I don't want the email sent until the report is generated.

此脚本构建报告,然后将电子邮件发送给我们的客户,因此我不希望在生成报告之前发送电子邮件。

Is this possible?

这可能吗?

Which should I use exec or cURL?

我应该使用exec或cURL?

2 个解决方案

#1

If its a local script, exec() or system() will do the trick.

如果它是本地脚本,exec()或system()将完成这一操作。

#2

You can call ajax request and get response from that.After getting response you can send another ajax request to send email.This code needs Jquery.

您可以调用ajax请求并从中获取响应。收到响应后,您可以发送另一个ajax请求来发送电子邮件。此代码需要Jquery。

Here is sample code for send ajax request using php.It is simple.

这是使用php发送ajax请求的示例代码。这很简单。

  var passdata ="partno=5"
  $.ajax({
        url: "yourpath/build_report.php",
        data:passdata ,
        async:false, 
        type: "POST",
        success: function(response){

               if(response=="true"){
                   /* call send email script */
                          emaildata="name=vcvx"+'email="vxvx@yyy.com";
                          $.ajax({
                                     url: "yourpath/build_report.php",
                                    data:emaildata,
                                     async:true, 
                                     type: "POST",
                                      success: function(response){
                                     }

                              }); 

                 }

         } });

#1