I've a A.php with somes inputs:
我有一些带有输入的A.php:
<input id="serverName" class="fullInput" type="text" name="serverName" placeholder="Nom du serveur" />
<input id="serverIP" class="fullInput" type="text" name="ip" placeholder="Adresse IP" />
<input id="serverWebsite" class="fullInput" type="text" name="site" placeholder="URL du site" />
I get them values in a B.js (and I re-use them for some things in JS)
我在B.js中得到它们的值(我在JS中重用它们用于某些东西)
var serverName = $.trim($('#serverName').val());
var serverIP = $.trim($('#serverIP').val());
var serverWebsite = $.trim($('#serverWebsite').val());
But now I've to write them in DB (php script) and I need to get this value again ? So it can be send in Ajax ?
但现在我要用DB(php脚本)编写它们,我需要再次获得这个值吗?那么可以用Ajax发送吗?
$.ajax({
url: "C.php",
method: "POST",
data: {
serverName: serverName.val(),
serverIP: serverIP.val(),
serverWebsite: serverWebsite.val()
},
dataType: "html"
});
Here my C.php will execute a post in DB with the variable serverName / serverWebsite / serverIP ? And this script can be launched with my ajax code ?
在这里,我的C.php将使用变量serverName / serverWebsite / serverIP在DB中执行一个帖子?这个脚本可以用我的ajax代码启动吗?
2 个解决方案
#1
0
Your JavaScript change some code in Ajax like this
你的JavaScript改变了Ajax中的一些代码
$.ajax({
url: "C.php",
method: "POST",
data: {serverName: serverName,serverIP: serverIP,serverWebsite: serverWebsite },
dataType: "html",
success: function(ans){
alert(ans);
}
});
and here your c.php file code like this
在这里你的c.php文件代码是这样的
<?php
$serverName = $_POST['serverName'];
$serverIP= $_POST['serverIP'];
$serverWebsite= $_POST['serverWebsite'];
//here you need to write mysql code to insert it in to database or whatever process
?>
this code useful for you :)
这段代码对你有用:)
#2
0
Your C.php would have code as below:
你的C.php会有如下代码:
<?php
$serverName = $_POST['serverName'];
$serverIP= $_POST['serverIP'];
$serverWebsite= $_POST['serverWebsite'];
//here you need to write mysql code to insert it in to database or whatever process you want to do with this variables.
?>
Thanks Amit
#1
0
Your JavaScript change some code in Ajax like this
你的JavaScript改变了Ajax中的一些代码
$.ajax({
url: "C.php",
method: "POST",
data: {serverName: serverName,serverIP: serverIP,serverWebsite: serverWebsite },
dataType: "html",
success: function(ans){
alert(ans);
}
});
and here your c.php file code like this
在这里你的c.php文件代码是这样的
<?php
$serverName = $_POST['serverName'];
$serverIP= $_POST['serverIP'];
$serverWebsite= $_POST['serverWebsite'];
//here you need to write mysql code to insert it in to database or whatever process
?>
this code useful for you :)
这段代码对你有用:)
#2
0
Your C.php would have code as below:
你的C.php会有如下代码:
<?php
$serverName = $_POST['serverName'];
$serverIP= $_POST['serverIP'];
$serverWebsite= $_POST['serverWebsite'];
//here you need to write mysql code to insert it in to database or whatever process you want to do with this variables.
?>
Thanks Amit