从另一个PHP脚本执行PHP脚本

How would I make my server run a php script by triggering it manually using php? Basically I have a pretty big cronjob file that is ran every 2 hours, but I want to be able to trigger the file manually myself without having to wait for it to load (i want it to be done on the server's side).

如何让我的服务器通过使用php手动触发运行PHP脚本？基本上我有一个相当大的cronjob文件，每2小时运行一次，但我希望能够自己手动触发文件，而不必等待它加载（我希望它在服务器端完成）。

EDIT: I want to execute the file from a php file... Not command line.

编辑：我想从php文件执行文件...不是命令行。

10 个解决方案

#1

You can invoke a PHP script manually from the command line

您可以从命令行手动调用PHP脚本

hello.php
<?php
 echo 'hello world!';
?>

Command line:
php hello.php

Output:
hello world!

See the documentation: http://php.net/manual/en/features.commandline.php

请参阅文档：http：//php.net/manual/en/features.commandline.php

EDIT OP edited the question to add a critical detail: the script is to be executed by another script.

编辑OP编辑了问题以添加关键细节：脚本将由另一个脚本执行。

There are a couple of approaches. First and easiest, you could simply include the file. When you include a file, the code within is "executed" (actually, interpreted). Any code that is not within a function or class body will be processed immediately. Take a look at the documentation for include (docs) and/or require (docs) (note: include_once and require_once are related, but different in an important way. Check out the documents to understand the difference) Your code would look like this:

有几种方法。首先也是最简单的，您可以简单地包含该文件。当您包含文件时，其中的代码将被“执行”（实际上，已解释）。任何不在函数或类体内的代码都将立即处理。看看包含（docs）和/或require（docs）的文档（注意：include_once和require_once是相关的，但在重要方面有所不同。查看文档以了解其中的区别）您的代码如下所示：

 include('hello.php');
 /* output
 hello world!
 */

Second and slightly more complex is to use shell_exec (docs). With shell_exec, you will call the php binary and pass the desired script as the argument. Your code would look like this:

第二个稍微复杂一点的是使用shell_exec（docs）。使用shell_exec，您将调用php二进制文件并将所需的脚本作为参数传递。你的代码看起来像这样：

$output = shell_exec('php hello.php');
echo "<pre>$output</pre>";
/* output
hello world!
*/

Finally, and most complex, you could use the CURL library to call the file as though it were requested via a browser. Check out the CURL library documentation here: http://us2.php.net/manual/en/ref.curl.php

最后，也是最复杂的，您可以使用CURL库来调用文件，就像通过浏览器请求它一样。查看CURL库文档：http：//us2.php.net/manual/en/ref.curl.php

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.myDomain.com/hello.php");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true)

$output = curl_exec($ch);
curl_close($ch);
echo "<pre>$output</pre>";
/* output
hello world!
*/

Documentation for functions used

所用功能的文档

Command line: http://php.net/manual/en/features.commandline.php
命令行：http：//php.net/manual/en/features.commandline.php
include: http://us2.php.net/manual/en/function.include.php
包括：http：//us2.php.net/manual/en/function.include.php
require: http://us2.php.net/manual/en/function.require.php
要求：http：//us2.php.net/manual/en/function.require.php
shell_exec: http://us2.php.net/manual/en/function.shell-exec.php
shell_exec：http：//us2.php.net/manual/en/function.shell-exec.php
curl_init: http://us2.php.net/manual/en/function.curl-init.php
curl_init：http：//us2.php.net/manual/en/function.curl-init.php
curl_setopt: http://us2.php.net/manual/en/function.curl-setopt.php
curl_setopt：http：//us2.php.net/manual/en/function.curl-setopt.php
curl_exec: http://us2.php.net/manual/en/function.curl-exec.php
curl_exec：http：//us2.php.net/manual/en/function.curl-exec.php
curl_close: http://us2.php.net/manual/en/function.curl-close.php
curl_close：http：//us2.php.net/manual/en/function.curl-close.php

#2

The OP refined his question to how a php script is called from a script. The php statement 'require' is good for dependancy as the script will stop if required script is not found.

OP对如何从脚本调用php脚本改进了他的问题。 php语句'require'有利于依赖，因为如果找不到所需的脚本，脚本将停止。

#!/usr/bin/php
<?
require '/relative/path/to/someotherscript.php';

/* The above script runs as though executed from within this one. */

printf ("Hello world!\n");

?>

#3

you can use the backtick notation:

你可以使用反引号表示法：

`php file.php`;

You can also put this at the top of the php file to indicate the interpreter:

您也可以将它放在php文件的顶部以指示解释器：

#!/usr/bin/php

Change it to where you put php. Then give execute permission on the file and you can call the file without specifying php:

把它改成你放PHP的地方。然后为该文件授予执行权限，您可以在不指定php的情况下调用该文件：

`./file.php`

If you want to capture the output of the script:

如果要捕获脚本的输出：

$output = `./file.php`;
echo $output;

#4

I prefer to use

我更喜欢使用

require_once('phpfile.php');

lots of options out there for you. and a good way to keep things clean.

有很多选择供你使用。以及保持清洁的好方法。

#5

If it is a linux box you would run something like:

如果它是一个Linux盒子你会运行如下：

php /folder/script.php

On Windows, you would need to make sure your php.exe file is part of your PATH, and do a similar approach to the file you want to run:

在Windows上，您需要确保您的php.exe文件是PATH的一部分，并对要运行的文件执行类似的方法：

php C:\folder\script.php

#6

On the command line:

在命令行上：

> php yourfile.php

#7

Open ssh and execute the command manually?

打开ssh并手动执行命令？

php /path/to/your/file.php

#8

to "chain" another php program from within your code, use "header"

从你的代码中“链接”另一个php程序，使用“header”

header("Location:index.php?page=menus");

头：;（ “位置index.php页面=菜单？”）

#9

<?php
$output = file_get_contents('http://host/path/another.php?param=value ');
echo $output;
?>

#10

-4

I think this is what you are looking for

我想这就是你要找的东西

<?php include ('Scripts/Php/connection.php');
//The connection.php script is executed inside the current file ?>

The script file can also be in a .txt format, it should still work, it does for me

脚本文件也可以是.txt格式，它仍然可以工作，它对我来说

e.g.

例如

<?php include ('Scripts/Php/connection.txt');
//The connection.txt script is executed inside the current file ?>

#1