Hi I am using Angular 2 final with router 3.0. I want to filter the events that are emitted from this.router.events
嗨,我正在使用Angular 2 final与路由器3.0。我想过滤从this.router.events发出的事件
What I want to do :
我想做的事 :
import 'rxjs/operator/filter';
//...
this.router.events
.filter((event:Event) => event instanceof NavigationEnd)
.subscribe(x => console.log(x))
event
can be instanceOf NavigationEnd
, NavigationStart
or RoutesRecognized
but I want only NavigationEnd
. But I get an error that
事件可以是instanceOf NavigationEnd,NavigationStart或RoutesRecognized但我只想要NavigationEnd。但我得到一个错误
Property 'filter' does not exist on type Observable<Event>
Observable
during compile time.
在编译期间。
When i import the whole rxjs
library the error disappears. What should I import to make it work without loading the full rxjs library ?
当我导入整个rxjs库时,错误消失。我应该导入什么才能使它工作而不加载完整的rxjs库?
6 个解决方案
#1
82
UPDATE
For RXJS 5.x
version:
对于RXJS 5.x版本:
import 'rxjs/add/operator/filter';
For RXJS 6.x
version:
对于RXJS 6.x版本:
import { filter } from 'rxjs/operators';
从'rxjs / operators'导入{filter};
The following rules have been designed by the RxJS team to help JavaScript developers refactor import paths:
RxJS团队设计了以下规则来帮助JavaScript开发人员重构导入路径:
rxjs/operators
: Contains all pipeable operators.rxjs /运算符:包含所有可管道运算符。
import { map, filter, scan } from 'rxjs/operators';
从'rxjs /运算符'导入{map,filter,scan};
rxjs
: Contains creation methods, types, schedulers, and utilities.rxjs:包含创建方法,类型,调度程序和实用程序。
import { Observable, Subject, asapScheduler, pipe, of, from, interval, merge, fromEvent } from 'rxjs';
从'rxjs'导入{Observable,Subject,asapScheduler,pipe,of,from,interval,merge,fromEvent};
#2
19
There are several possible fixes for this scenario.
此方案有几种可能的修复方法。
1) Use pipeable operators
Pipeable operators are meant to be a better approach for pulling in just the operators you need than the "patch" operators found in rxjs/add/operator/*
与rxjs / add / operator / *中的“补丁”运算符相比,可管理运算符是一种更好的方法,可以提供所需的运算符。
import { filter } from 'rxjs/operators';
// ..
this.router.events.pipe(
filter((event:Event) => event instanceof NavigationEnd)
).subscribe(x => console.log(x))
2) Use 'rxjs/add/operator/filter'
Change the import statement to import 'rxjs/add/operator/filter'
. This will modify Observable.prototype
and add filter
method to an every instance of the Observable class.
更改import语句以导入'rxjs / add / operator / filter'。这将修改Observable.prototype并将filter方法添加到Observable类的每个实例。
There are two consequences:
有两个后果:
- it is enough to execute the import statement just once per the application
- in a shared library/npm package this might bring some confusion to a library consumer (
filter()
method will magically appear underObservable
while using the library)
每个应用程序只执行一次import语句就足够了
在共享库/ npm包中,这可能会给库使用者带来一些混淆(filter()方法在使用库时会神奇地出现在Observable下)
3) Leave the operator import but change how it is called
The statement import 'rxjs/operator/filter'
is perfectly valid. It will import just the operator. This approach will not mess with the Observable.prototype
. On downside it will make it more difficult to chain several operators.
语句import'rxjs / operator / filter'完全有效。它只会导入运营商。这种方法不会弄乱Observable.prototype。在不利方面,它将使连锁几个运营商变得更加困难。
import 'rxjs/operator/filter'; // This is valid import statement.
// It will import the operator without
// modifying Observable prototype
// ..
// Change how the operator is called
filter.call(
this.router.events,
(event:Event) => event instanceof NavigationEnd
).subscribe(x => console.log(x));
More details: Pipeable Operators
更多细节:可管理的操作员
#3
5
Angular Update(5.x to 6.x) also comes with update of rxjs from 5.x to 6.x So simply add
角度更新(5.x到6.x)还附带了从5.x到6.x的rxjs更新所以简单地添加
import { filter } from 'rxjs/operators';
then
this.router.events.pipe(
filter((event:Event) => event instanceof NavigationEnd)
).subscribe(x => console.log(x))
Hope That helps someone
希望这有助于某人
#4
4
After updating to Rxjs 6 with Angular 6 upgrade
在使用Angular 6升级更新到Rxjs 6之后
import { map, filter, scan } from 'rxjs/operators';
...
this.registrationForm.valueChanges
.pipe(
filter(() => this.registrationForm.valid),
map((registrationForm: any) => {
this.registrationVm.username = registrationForm.username;
this.registrationVm.password = registrationForm.password;
this.registrationVm.passwordConfirm = registrationForm.passwordConfirm;
})
)
.subscribe();
#5
2
The easiest way is to just
最简单的方法就是
npm install rxjs-compat
which will make any version differences magically go away!
这将使任何版本差异神奇地消失!
#6
0
Please check the type of Event here -> .filter((event:Event)
请在这里检查事件的类型 - > .filter((事件:事件)
#1
82
UPDATE
For RXJS 5.x
version:
对于RXJS 5.x版本:
import 'rxjs/add/operator/filter';
For RXJS 6.x
version:
对于RXJS 6.x版本:
import { filter } from 'rxjs/operators';
从'rxjs / operators'导入{filter};
The following rules have been designed by the RxJS team to help JavaScript developers refactor import paths:
RxJS团队设计了以下规则来帮助JavaScript开发人员重构导入路径:
rxjs/operators
: Contains all pipeable operators.rxjs /运算符:包含所有可管道运算符。
import { map, filter, scan } from 'rxjs/operators';
从'rxjs /运算符'导入{map,filter,scan};
rxjs
: Contains creation methods, types, schedulers, and utilities.rxjs:包含创建方法,类型,调度程序和实用程序。
import { Observable, Subject, asapScheduler, pipe, of, from, interval, merge, fromEvent } from 'rxjs';
从'rxjs'导入{Observable,Subject,asapScheduler,pipe,of,from,interval,merge,fromEvent};
#2
19
There are several possible fixes for this scenario.
此方案有几种可能的修复方法。
1) Use pipeable operators
Pipeable operators are meant to be a better approach for pulling in just the operators you need than the "patch" operators found in rxjs/add/operator/*
与rxjs / add / operator / *中的“补丁”运算符相比,可管理运算符是一种更好的方法,可以提供所需的运算符。
import { filter } from 'rxjs/operators';
// ..
this.router.events.pipe(
filter((event:Event) => event instanceof NavigationEnd)
).subscribe(x => console.log(x))
2) Use 'rxjs/add/operator/filter'
Change the import statement to import 'rxjs/add/operator/filter'
. This will modify Observable.prototype
and add filter
method to an every instance of the Observable class.
更改import语句以导入'rxjs / add / operator / filter'。这将修改Observable.prototype并将filter方法添加到Observable类的每个实例。
There are two consequences:
有两个后果:
- it is enough to execute the import statement just once per the application
- in a shared library/npm package this might bring some confusion to a library consumer (
filter()
method will magically appear underObservable
while using the library)
每个应用程序只执行一次import语句就足够了
在共享库/ npm包中,这可能会给库使用者带来一些混淆(filter()方法在使用库时会神奇地出现在Observable下)
3) Leave the operator import but change how it is called
The statement import 'rxjs/operator/filter'
is perfectly valid. It will import just the operator. This approach will not mess with the Observable.prototype
. On downside it will make it more difficult to chain several operators.
语句import'rxjs / operator / filter'完全有效。它只会导入运营商。这种方法不会弄乱Observable.prototype。在不利方面,它将使连锁几个运营商变得更加困难。
import 'rxjs/operator/filter'; // This is valid import statement.
// It will import the operator without
// modifying Observable prototype
// ..
// Change how the operator is called
filter.call(
this.router.events,
(event:Event) => event instanceof NavigationEnd
).subscribe(x => console.log(x));
More details: Pipeable Operators
更多细节:可管理的操作员
#3
5
Angular Update(5.x to 6.x) also comes with update of rxjs from 5.x to 6.x So simply add
角度更新(5.x到6.x)还附带了从5.x到6.x的rxjs更新所以简单地添加
import { filter } from 'rxjs/operators';
then
this.router.events.pipe(
filter((event:Event) => event instanceof NavigationEnd)
).subscribe(x => console.log(x))
Hope That helps someone
希望这有助于某人
#4
4
After updating to Rxjs 6 with Angular 6 upgrade
在使用Angular 6升级更新到Rxjs 6之后
import { map, filter, scan } from 'rxjs/operators';
...
this.registrationForm.valueChanges
.pipe(
filter(() => this.registrationForm.valid),
map((registrationForm: any) => {
this.registrationVm.username = registrationForm.username;
this.registrationVm.password = registrationForm.password;
this.registrationVm.passwordConfirm = registrationForm.passwordConfirm;
})
)
.subscribe();
#5
2
The easiest way is to just
最简单的方法就是
npm install rxjs-compat
which will make any version differences magically go away!
这将使任何版本差异神奇地消失!
#6
0
Please check the type of Event here -> .filter((event:Event)
请在这里检查事件的类型 - > .filter((事件:事件)