用一个&符号替换最后一个逗号。

时间:2021-08-04 22:33:59

I have searched everywhere but can't find a solution that works for me.

我到处都找过了,但找不到适合我的解决方案。

I have the following:

我有以下几点:

$bedroom_array = array($studio, $one_bed, $two_bed, $three_bed, $four_bed);

For this example lets say:

对于这个例子,我们说:

$studio = '1';
$one_bed = '3';
$two_bed = '3';

I then use the implode function to put a comma in between all the values:

然后我使用内爆函数在所有值之间加一个逗号:

$bedroom_list = implode(", ", array_filter($bedroom_array));
echo $bedroom_list;

This then outputs:

然后输出:

1, 2, 3

1、2、3

What I want to do is find the last comma in the string and replace it with an &, so it would read:

我要做的是找到字符串中的最后一个逗号,然后用&替换,这样它就会是:

1, 2 & 3

1、2和3

The string will not always be this long, it can be shorter or longer, e.g. 1, 2, 3, 4 and so on. I have looked into using substr but am not sure if this will work for what I need?

弦不会总是这么长,它可以更短或更长,例如1、2、3、4等等。我已经考虑过使用substr,但不确定它是否可以满足我的需要?

7 个解决方案

#1


25  

Pop off the last element, implode the rest together then stick the last one back on.

取出最后一个元素,将其余元素内爆,然后将最后一个元素粘在一起。

$bedroom_array = array('studio', 'one_bed', 'two_bed', 'three_bed', 'four_bed');
$last = array_pop($bedroom_array);
$string = count($bedroom_array) ? implode(", ", $bedroom_array) . " & " . $last : $last;

Convert & to the entity & if necessary.

转换和到实体&放大器;如果有必要的话)。

#2


5  

if you have comma separated list of words you may use:

如果你有逗号分隔的单词列表,你可以使用:

$keyword = "hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf, sdgdfg";
$keyword = preg_replace('/,([^,]*)$/', ' & \1', $keyword);
echo $keyword;

$关键字= "hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf, sdgdfg";关键词=美元preg_replace(' /((^,)*)$ / ',' & \ 1 ',美元关键字);echo $关键词;

it will output: hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf & sdgdfg

它将输出:hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf和sdgdfg

#3


1  

A one-liner alternative, that will work for any size array ($b = $bedroom_array):

一个简单的选择,适用于任何大小的数组($b = $bedroom_array):

echo count($b) <= 1 ? reset($b) : join(', ', array_slice($b, 0, -1)) . " & " . end($b); 

#4


1  

function fancy_implode($arr){
    array_push($arr, implode(' and ', array_splice($arr, -2)));
    return implode(', ', $arr);
}

I find this easier to read/understand and use

我发现这个更容易阅读/理解和使用

  • Does not modify the original array
  • 不修改原始数组吗
  • Does not use regular expressions as those may fail if strings in the array contain commas, there could be a valid reason for that, something like this: array('Shirts (S, M, L)', 'Pants (72 x 37, 72 x 39)');
  • 不使用正则表达式,因为如果数组中的字符串包含逗号,可能会失败,有一个合理的理由,比如:数组('Shirts (S, M, L)', 'Pants (72 x 37, 72 x 39)';
  • Delimiters don't have to be of the same length as with some of the other solutions
  • 分隔符不必与其他一些解决方案的长度相同

#5


0  

$bedroom_list = implode(", ", array_filter($bedroom_array));

$vars =  $bedroom_list;

$last = strrchr($vars,",");

$last_ = str_replace(",","&",$last);

echo str_replace("$last","$last_",$vars);

#6


0  

<?php
$string = "3, 4, 5";
echo $string = preg_replace('/,( \d)$/', ' &\1', $string);
?>

#7


0  

strrpos finds the last occurrance of a specified string. $str = '1, 2, 3';

strrpos发现指定字符串的最后一个发生。$str = ' 1,2,3 ';

$index = strrpos( $str, ',' ); 
if( $index !== FALSE )
    $str[ $index ] = '&'; 

#1


25  

Pop off the last element, implode the rest together then stick the last one back on.

取出最后一个元素,将其余元素内爆,然后将最后一个元素粘在一起。

$bedroom_array = array('studio', 'one_bed', 'two_bed', 'three_bed', 'four_bed');
$last = array_pop($bedroom_array);
$string = count($bedroom_array) ? implode(", ", $bedroom_array) . " & " . $last : $last;

Convert & to the entity &amp; if necessary.

转换和到实体&放大器;如果有必要的话)。

#2


5  

if you have comma separated list of words you may use:

如果你有逗号分隔的单词列表,你可以使用:

$keyword = "hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf, sdgdfg";
$keyword = preg_replace('/,([^,]*)$/', ' & \1', $keyword);
echo $keyword;

$关键字= "hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf, sdgdfg";关键词=美元preg_replace(' /((^,)*)$ / ',' & \ 1 ',美元关键字);echo $关键词;

it will output: hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf & sdgdfg

它将输出:hello, sadasd, sdfgdsfg,sadfsdafsfd, ssdf和sdgdfg

#3


1  

A one-liner alternative, that will work for any size array ($b = $bedroom_array):

一个简单的选择,适用于任何大小的数组($b = $bedroom_array):

echo count($b) <= 1 ? reset($b) : join(', ', array_slice($b, 0, -1)) . " & " . end($b); 

#4


1  

function fancy_implode($arr){
    array_push($arr, implode(' and ', array_splice($arr, -2)));
    return implode(', ', $arr);
}

I find this easier to read/understand and use

我发现这个更容易阅读/理解和使用

  • Does not modify the original array
  • 不修改原始数组吗
  • Does not use regular expressions as those may fail if strings in the array contain commas, there could be a valid reason for that, something like this: array('Shirts (S, M, L)', 'Pants (72 x 37, 72 x 39)');
  • 不使用正则表达式,因为如果数组中的字符串包含逗号,可能会失败,有一个合理的理由,比如:数组('Shirts (S, M, L)', 'Pants (72 x 37, 72 x 39)';
  • Delimiters don't have to be of the same length as with some of the other solutions
  • 分隔符不必与其他一些解决方案的长度相同

#5


0  

$bedroom_list = implode(", ", array_filter($bedroom_array));

$vars =  $bedroom_list;

$last = strrchr($vars,",");

$last_ = str_replace(",","&",$last);

echo str_replace("$last","$last_",$vars);

#6


0  

<?php
$string = "3, 4, 5";
echo $string = preg_replace('/,( \d)$/', ' &\1', $string);
?>

#7


0  

strrpos finds the last occurrance of a specified string. $str = '1, 2, 3';

strrpos发现指定字符串的最后一个发生。$str = ' 1,2,3 ';

$index = strrpos( $str, ',' ); 
if( $index !== FALSE )
    $str[ $index ] = '&';