I have a variable that is being defined as
我有一个被定义为的变量
$var .= "value";
How does the use of the dot equal function?
如何使用点等功能?
4 个解决方案
#1
38
It's the concatenating assignment operator. It works similarly to:
它是连接赋值运算符。它的工作方式类似于:
$var = $var . "value";
$x .=
differs from $x = $x .
in that the former is in-place, but the latter re-assigns $x
.
$ x。=与$ x = $ x不同。因为前者是就地的,但后者重新分配了$ x。
#2
14
This is for concatenation
这是用于连接
$var = "test";
$var .= "value";
echo $var; // this will give you testvalue
#3
5
the ".
" operator is the string concatenation operator. and ".=
" will concatenate strings.
“。” operator是字符串连接运算符。和“。=”将连接字符串。
Example:
例:
$var = 1;
$var .= 20;
This is same as:
这与:
$var = 1 . 20;
the ".=
" operator is a string operator, it first converts the values to strings; and since ".
" means concatenate / append, the result is the string "120
".
“。=”运算符是一个字符串运算符,它首先将值转换为字符串;从那以后“。”表示连接/追加,结果是字符串“120”。
#4
0
In fact when we check the variable with:
事实上,当我们检查变量时:
var_dump($var);
The result will be:
string(202) "120"
i.e. the content of the variable will be changed to 120!
Not 1 or 20!
结果将是:string(202)“120”,即变量的内容将改为120!不是1或20!
#1
38
It's the concatenating assignment operator. It works similarly to:
它是连接赋值运算符。它的工作方式类似于:
$var = $var . "value";
$x .=
differs from $x = $x .
in that the former is in-place, but the latter re-assigns $x
.
$ x。=与$ x = $ x不同。因为前者是就地的,但后者重新分配了$ x。
#2
14
This is for concatenation
这是用于连接
$var = "test";
$var .= "value";
echo $var; // this will give you testvalue
#3
5
the ".
" operator is the string concatenation operator. and ".=
" will concatenate strings.
“。” operator是字符串连接运算符。和“。=”将连接字符串。
Example:
例:
$var = 1;
$var .= 20;
This is same as:
这与:
$var = 1 . 20;
the ".=
" operator is a string operator, it first converts the values to strings; and since ".
" means concatenate / append, the result is the string "120
".
“。=”运算符是一个字符串运算符,它首先将值转换为字符串;从那以后“。”表示连接/追加,结果是字符串“120”。
#4
0
In fact when we check the variable with:
事实上,当我们检查变量时:
var_dump($var);
The result will be:
string(202) "120"
i.e. the content of the variable will be changed to 120!
Not 1 or 20!
结果将是:string(202)“120”,即变量的内容将改为120!不是1或20!