I am trying to memcpy from one ptr to another. I know the size that I want to copy. Both the destination and source pointers are void pointers. Is this valid? Does it actually copy the ELEMENT_SIZE (integer like 128) from source to the destination? I know this is not the most ideal thing to do. But I want to know if this works.
我试图从一个ptr到另一个ptr。我知道我要复制的大小。目标和源指针都是void指针。这有效吗？它是否实际上将ELEMENT_SIZE（整数类似于128）从源复制到目标？我知道这不是最理想的事情。但我想知道这是否有效。
memcpy(to_add, element_ptr, ELEMENT_SIZE);
3 个解决方案
#1
1
Does it actually copy the ELEMENT_SIZE (integer like 128) from source to the destination?
它是否实际上将ELEMENT_SIZE（整数类似于128）从源复制到目标？
Yes, If you know the size information,then its working fine.
是的，如果您知道尺寸信息，那么它的工作正常。
See the reference link : http://www.cplusplus.com/reference/cstring/memcpy/
请参阅参考链接：http：//www.cplusplus.com/reference/cstring/memcpy/
#2
1
Parameter descriptions for memcpy from the documentation:
文档中memcpy的参数描述：
void * memcpy ( void * destination, const void * source, size_t num );void * memcpy（void * destination，const void * source，size_t num）;
destination: Pointer to the destination array where the content is to be copied, type-casted to a pointer of type void*.destination：指向要复制内容的目标数组的指针，类型转换为void *类型的指针。
source: Pointer to the source of data to be copied, type-casted to a pointer of type const void*.source：指向要复制的数据源的指针，类型转换为const void *类型的指针。
num: Number of bytes to copy. size_t is an unsigned integral type.num：要复制的字节数。 size_t是无符号整数类型。
memcpy simply takes num bytes starting from the address source and copies them to memory starting at address destination.
memcpy只需从地址源开始占用num个字节，然后从地址目的地开始将它们复制到内存中。
A pointer is a fixed length memory address, regardless of type. It does not matter whether the pointer is char * (points to character data), int * (points to integer data), or void * (points to data of unknown type), it still just points to memory.
无论类型如何，指针都是固定长度的存储器地址。无论指针是char *（指向字符数据），int *（指向整数数据）还是void *（指向未知类型的数据）都无关紧要，它仍指向内存。
Because memcpy copies an explicit number of bytes, the type of data being pointed to is irrelevant; it just need memory addresses to data.
因为memcpy复制了一个明确的字节数，所指向的数据类型是无关紧要的;它只需要数据的内存地址。
#3
0
It does not matter what pointer it is really. It is a very plain process of having two memory addresses and engaging a copy.
它究竟是什么指针并不重要。这是一个非常简单的过程，有两个内存地址和一个副本。
#1
1
Does it actually copy the ELEMENT_SIZE (integer like 128) from source to the destination?
它是否实际上将ELEMENT_SIZE（整数类似于128）从源复制到目标？
Yes, If you know the size information,then its working fine.
是的，如果您知道尺寸信息，那么它的工作正常。
See the reference link : http://www.cplusplus.com/reference/cstring/memcpy/
请参阅参考链接：http：//www.cplusplus.com/reference/cstring/memcpy/
#2
1
Parameter descriptions for memcpy from the documentation:
文档中memcpy的参数描述：
void * memcpy ( void * destination, const void * source, size_t num );void * memcpy（void * destination，const void * source，size_t num）;
destination: Pointer to the destination array where the content is to be copied, type-casted to a pointer of type void*.destination：指向要复制内容的目标数组的指针，类型转换为void *类型的指针。
source: Pointer to the source of data to be copied, type-casted to a pointer of type const void*.source：指向要复制的数据源的指针，类型转换为const void *类型的指针。
num: Number of bytes to copy. size_t is an unsigned integral type.num：要复制的字节数。 size_t是无符号整数类型。
memcpy simply takes num bytes starting from the address source and copies them to memory starting at address destination.
memcpy只需从地址源开始占用num个字节，然后从地址目的地开始将它们复制到内存中。
A pointer is a fixed length memory address, regardless of type. It does not matter whether the pointer is char * (points to character data), int * (points to integer data), or void * (points to data of unknown type), it still just points to memory.
无论类型如何，指针都是固定长度的存储器地址。无论指针是char *（指向字符数据），int *（指向整数数据）还是void *（指向未知类型的数据）都无关紧要，它仍指向内存。
Because memcpy copies an explicit number of bytes, the type of data being pointed to is irrelevant; it just need memory addresses to data.
因为memcpy复制了一个明确的字节数，所指向的数据类型是无关紧要的;它只需要数据的内存地址。
#3
0
It does not matter what pointer it is really. It is a very plain process of having two memory addresses and engaging a copy.
它究竟是什么指针并不重要。这是一个非常简单的过程，有两个内存地址和一个副本。