匹配短语的正则表达式以问号结尾

I'm trying to figure out a javascript regex that'll match an exact phrase that ends with a question mark, but isn't wrapped in quotes. So far I have this, which matches the phrase "some phrase", but I can't figure out how to match "some phrase?". Any help would be greatly appreciated.

我试图找出一个javascript正则表达式，它匹配一个以问号结尾的精确短语，但不包含在引号中。到目前为止，我有这个，它匹配短语“some phrase”，但我无法弄清楚如何匹配“某些短语？”。任何帮助将不胜感激。

(?<!"|')\some phrase\b(?!"|')

2 个解决方案

#1

Lookbehinds don't exist in JavaScript. Use the following pattern:
(?:[^"']|^)(some phrase\?)(?!["']). [^"']|^ means: any non-quote character or the beginning of a string.

JavaScript中不存在Lookbehinds。使用以下模式：（？：[^“'] | ^）（某些短语\？）（？！[”']）。 [^“'] | ^表示：任何非引号字符或字符串的开头。

Example:

例：

var text = "....";
var pattern = /(?:[^"']|^)(some phrase\?)(?!["'])/;
var string = text.match(pattern);
var desiredString = string[1]; //Get the grouped text

var patternWithNQuoteGrouped = /([^"']|^)(some phrase\?)(?!["'])/;//Notice: No ?:
var replaceString = text.replace(patternWithNQuoteGrouped, '$1$2');
//$1 = non-quote character $2 = matched phrase

The parentheses around the phrase mark a referable group. (?: means: Create a group, but dereference it. To refer back to it, see the example code. Because lookbehinds don't exist in JavaScript, it's not possible to create a pattern which checks whether a prefix does not exist.

短语周围的括号标记可参考组。（？：表示：创建一个组，但取消引用它。要返回它，请参阅示例代码。由于JavaScript中不存在lookbehinds，因此无法创建检查前缀是否不存在的模式。

#2

Try this:

尝试这个：

var expr = /(^|(?!["']).)(some phrase\?)($|(?!["']).)/;
if (expr.test(searchText)) {
    var matchingPhrase = RegExp.$2;
}

http://jsfiddle.net/gilly3/zCUsg/

#1