在Python中以某种扩展名结尾的文件名匹配的简明方法?

What's the canonical way to handle to retrieve all files in a directory that end in a particular extension, e.g. "All files that end in .ext or .ext2 in a case insensitive way?" One way is using os.listdir and re module:

在以特定扩展结束的目录中检索所有文件的标准方法是什么?“所有的文件都以。ext或。ext2结尾，不区分大小写吗?”一种方法是使用操作系统。listdir和re模块:

import re
files = os.listdir(mydir)
# match in case-insensitive way all files that end in '.ext' or '.ext2'
p = re.compile(".ext(2)?$", re.IGNORECASE)
matching_files = [os.path.join(mydir, f) for f in files if p.search(x) is not None]

Is there a preferred way to do this more concisely with glob or fnmatch? The annoyance with listdir is that one has to handle the path all the time, by prepending with os.path.join the directory to the basename of each file it returns.

使用glob或fnmatch有更简洁的方法吗?listdir带来的麻烦是，必须始终通过使用os.path预挂来处理路径。将目录连接到它返回的每个文件的basename。

1 个解决方案

#1

How about:

如何:

>>> import glob
>>> glob.glob("testdir/*")
['testdir/a.txt', 'testdir/b.txt', 'testdir/d.ext', 'testdir/c.ExT2']
>>> [f for f in glob.glob("testdir/*") if f.lower().endswith((".ext", ".ext2"))]
['testdir/d.ext', 'testdir/c.ExT2']