I would like to pass something like this: 6 3 * into argv so that
我想要传递这样的信息:6 3 *进入argv。
*argv[1] = '6'
*argv[2] = '3'
*argv[3] = '*'
but what ends up happening is the asterisk causes a bunch of related file names to be passed to argv, and I cant find any info on why this is...
但是最终的结果是星号会导致一些相关的文件名被传递给argv，我找不到任何关于这个的信息。
2 个解决方案
#1
2
Use \ to escape the * character when you call the program:
当你调用程序时，使用\来逃避*字符:
./tst 6 3 \*
#2
1
That's a problem between you and your shell, nothing to do with C. Launch your program like this:
这是你和你的shell之间的问题，与c无关。启动你的程序:
./a.out 666 3333 "*"
#1
2
Use \ to escape the * character when you call the program:
当你调用程序时，使用\来逃避*字符:
./tst 6 3 \*
#2
1
That's a problem between you and your shell, nothing to do with C. Launch your program like this:
这是你和你的shell之间的问题，与c无关。启动你的程序:
./a.out 666 3333 "*"