如何在Java中将JSON数组对象转换为XML时添加包装器

I want to convert JSON array into XML, but during conversion it generates invalid XML file:

我想将JSON数组转换为XML,但在转换过程中它会生成无效的XML文件:

String str = "{ 'test' : [ {'a' : 'A'},{'b' : 'B'}]}"; 
JSONObject json = new JSONObject(str);
String xml = XML.toString(json);

I used above code as suggested in Converting JSON to XML in Java

我使用上面的代码,如在Java中将JSON转换为XML中所建议的那样

But if I tried to convert JSON object into XML it give invalid XML (error: The markup in the document following the root element must be well-formed.) which is

但是,如果我尝试将JSON对象转换为XML,则会产生无效的XML(错误:根元素后面的文档中的标记必须格式正确。)这是

<test><a>A</a></test><test><b>B</b></test>

Can anybody please tell me how to get valid XML from JSON array or how to wrap JSON array while converting into XML?

任何人都可以告诉我如何从JSON数组获取有效的XML或如何在转换为XML时包装JSON数组?

Thanks in advance.

提前致谢。

1 个解决方案

#1

XML documents can have only one root element. Your XML result is actually:

XML文档只能有一个根元素。您的XML结果实际上是:

<test>
    <a>A</a>
</test>
<test>
    <b>B</b>
</test>

where the second test element is clearly after the document root element closing tag. XML.toString has a nice overload accepting object and string to enclose the result XML:

其中第二个测试元素明显位于文档根元素结束标记之后。 XML.toString有一个很好的重载接受对象和字符串来包含结果XML:

final String json = getPackageResourceString(Q43440480.class, "doc.json");
final JSONObject jsonObject = new JSONObject(json);
final String xml = XML.toString(jsonObject, "tests");
System.out.println(xml);

Now the output XML is well-formed:

现在输出XML格式正确:

<tests>
    <test>
        <a>A</a>
    </test>
    <test>
        <b>B</b>
    </test>
</tests>

#1