First the DispatcherServlet is invoked by the Servlet Container.
The DispatcherServlet finds a mapping which maps to the home method of your Controller and the home method returns a view name "HelloWorld"
Now the DispatcherServlet uses a View Resolver (your InternalResourceViewResolver) to find the View to render the model through, since the name is "HelloWorld", this maps to the /WEB-INF/view/HelloWorld.html view.
Now essentially a call is made to RequestDispatcher.forward("/WEB-INF/views/HelloWorld.html",....
The Servlet container at this point tries to find the servlet which can handle /WEB-INF/views/HellowWorld.html uri - if it had been a .jsp there is a JSPServlet registered which can handle rendering the jsp, however for *.html there is no servlet registered, so the call ends up with the "default servlet", which is registered with a servlet-mapping of / which probably your DispatcherServlet is.
Now the Dispatcher servlet does not find a controller to handle request for /WEB-INF/views/HelloWorld.html and hence the message that you are seeing
已经很清楚的告诉我们了即使你：
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/views/"/>
<property name="suffix" value=".html"/>
</bean>
这样配置了
但是你可爱的Web 容器并不知道，你到底要干嘛？解析的是个What.所以你需要在web中注册一下：
<servlet-mapping>
<servlet-name>jsp</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
顺道说一句JSP不是和html一样的，只是个文件后缀名而已，一句半句也说不清楚，感兴趣的朋友可以翻翻相关资料。