php将图片以二进制保存到mysql数据库并显示

一.存储图片的数据表结构：

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--
-- 表的结构 `image`
--

CREATE TABLE IF NOT EXISTS `image` (
  `id` int ( 3 ) NOT NULL AUTO_INCREMENT,
  `name` varchar( 100 ) CHARACTER SET utf8 NOT NULL ,
  `pic` blob NOT NULL ,
  `type` varchar( 50 ) CHARACTER SET utf8 NOT NULL ,
  `date` datetime NOT NULL ,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT= 1 ;

--
-- 转存表中的数据 `image`
--

二.php将图片以二进制保存到mysql数据库中：

(1)连接数据库文件：conn.php:

     PHP Code  
  

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<?php
$conn = mysql_connect( 'localhost' , 'root' , '' );
mysql_select_db( 'study' , $conn);
mysql_query( "SET NAMES UTF-8" );
?>

(2)图片上传并以二进制保存到数据库文件：upload.php

     PHP Code  
  

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<?php
include ( './conn.php' );
if ( $_POST [ 'submit' ]) {
     if ( $_FILES [ 'image' ][ 'size' ]) {
        $names = $_FILES [ 'image' ][ 'name' ];
        $arr   = explode( '.' , $names);
        $name  = $arr[ 0 ]; //图片名称
        $date  = date( 'Y-m-d H:i:s' ); //上传日期
        $fp    = fopen( $_FILES [ 'image' ][ 'tmp_name' ], 'rb' );
        $type  = $_FILES [ 'image' ][ 'type' ];
         if (!$fp) {
            showInfo( '读取图片失败！' );
        } else {
            $image = addslashes(fread($fp, filesize( $_FILES [ 'image' ][ 'tmp_name' ])));
             if ($image) {
                $q      = "insert into image (name, pic, type, date) values ('$name','$image','$type','$date')" ;
                $result = mysql_query($q);
                 if ($result) {
                    showInfo( '上传成功！' );
                } else {
                    showInfo( '上传失败！' );
                }

            } else {
                showInfo( '请选择要上传的文件！' );
            }
        }

    } else {
        showInfo( '请选择要上传的文件！' );
    }
}

function showInfo($info)
{
     echo "<html><head><meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />" ;
     echo "<meta http-equiv='refresh' content='1;url=index.php'>" ;
     echo "</head>" ;
     echo "<body>" . $info . "……</body>" ;
     echo "</html>" ;
}
?>

三.从数据库中读取以二进制保存的图片并显示:image.php

     PHP Code  
  

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<?php
include ( './conn.php' );

$id     = $_GET [ 'id' ];
$sql    = "select * from image where id='$id'" ;
$result = mysql_query($sql, $conn);
if (!$result)
     die ( "读取图片失败！" );
$num = mysql_num_rows($result);
if ($num < 1 )
     die ( "暂无图片" );
$data = mysql_result($result, 0 , 'pic' );
$type = mysql_result($result, 0 , 'type' );
mysql_close($id);
Header( "Content-type: $type" );
echo $data;
?>

四.上传并显示图片的页面：index.php

     PHP Code  
  

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<?php
include ( './conn.php' );
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
        "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" >

<html xmlns= "http://www.w3.org/1999/xhtml" lang= "en_US" xml:lang= "en_US" >

<head>
<meta http-equive= "Content-Type" content=text/html charset=utf-8>
  <title> </title>
</head>
<body>
<form method= 'post' action= './upload.php' enctype= "multipart/form-data" >
<input type= "file" name= "image" />
<input type= "submit" name= "submit" value= "上传" />
</form>

<table>
<?php
$ret = mysql_query( 'select * from image order by id desc' );
if ($ret) {
     while ($row = mysql_fetch_array($ret)) {
?>
<tr>
<td style= 'width:170px;' >
<img src= "image.php?id=<?php
         echo $row[id];
?> "  width=" 170 " height=" 150 " border=" 0 ">
<div style= 'text-align:center;' ><?php
         echo $row[ 'name' ];
?></div>
<?php
         echo $row[ 'date' ];
?>
</td>
</tr>
<?php
    }
}
?>
</table>

</body>
</html>

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php将图片以二进制保存到mysql数据库并显示

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