php将图片以二进制保存到mysql数据库并显示

一.存储图片的数据表结构：

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--
-- 表的结构 `image`
--

CREATE TABLE IF NOT EXISTS `image` (
  `id` int(3) NOT NULL AUTO_INCREMENT,
  `name` varchar(100) CHARACTER SET utf8 NOT NULL,
  `pic` blob NOT NULL,
  `type` varchar(50) CHARACTER SET utf8 NOT NULL,
  `date` datetime NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

--
-- 转存表中的数据 `image`
--

二.php将图片以二进制保存到mysql数据库中： (1)连接数据库文件：conn.php: PHP Code

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<?php
$conn = mysql_connect('localhost', 'root', '');
mysql_select_db('study', $conn);
mysql_query("SET NAMES UTF-8");
?>

(2)图片上传并以二进制保存到数据库文件：upload.php PHP Code

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<?php
include('./conn.php');
if ($_POST['submit']) {
    if ($_FILES['image']['size']) {
        $names = $_FILES['image']['name'];
        $arr   = explode('.', $names);
        $name  = $arr[0]; //图片名称
        $date  = date('Y-m-d H:i:s'); //上传日期
        $fp    = fopen($_FILES['image']['tmp_name'], 'rb');
        $type  = $_FILES['image']['type'];
        if (!$fp) {
            showInfo('读取图片失败！');
        } else {
            $image = addslashes(fread($fp, filesize($_FILES['image']['tmp_name'])));
            if ($image) {
                $q      = "insert into image (name, pic, type, date) values ('$name','$image','$type','$date')";
                $result = mysql_query($q);
                if ($result) {
                    showInfo('上传成功！');
                } else {
                    showInfo('上传失败！');
                }

            } else {
                showInfo('请选择要上传的文件！');
            }
        }

    } else {
        showInfo('请选择要上传的文件！');
    }
}

function showInfo($info)
{
    echo "<html><head><meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />";
    echo "<meta http-equiv='refresh' content='1;url=index.php'>";
    echo "</head>";
    echo "<body>" . $info . "……</body>";
    echo "</html>";
}
?>

三.从数据库中读取以二进制保存的图片并显示:image.php PHP Code

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<?php
include('./conn.php');

$id     = $_GET['id'];
$sql    = "select * from image where id='$id'";
$result = mysql_query($sql, $conn);
if (!$result)
    die("读取图片失败！");
$num = mysql_num_rows($result);
if ($num < 1)
    die("暂无图片");
$data = mysql_result($result, 0, 'pic');
$type = mysql_result($result, 0, 'type');
mysql_close($id);
Header("Content-type: $type");
echo $data;
?>

四.上传并显示图片的页面：index.php PHP Code

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<?php
include('./conn.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
       "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en_US" xml:lang="en_US">

<head>
<meta http-equive="Content-Type" content=text/html charset=utf-8>
  <title> </title>
</head>
<body>
<form method='post' action='./upload.php' enctype="multipart/form-data">
<input type="file" name="image" />
<input type="submit" name="submit" value="上传" />
</form>

<table>
<?php
$ret = mysql_query('select * from image order by id desc');
if ($ret) {
    while ($row = mysql_fetch_array($ret)) {
?>
<tr>
<td style='width:170px;'>
<img src="image.php?id=<?php
        echo $row[id];
?>"  width="170" height="150" border="0">
<div style='text-align:center;'><?php
        echo $row['name'];
?></div>
<?php
        echo $row['date'];
?>
</td>
</tr>
<?php
    }
}
?>
</table>

</body>
</html>

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php将图片以二进制保存到mysql数据库并显示

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