两个日期之间的SQL时差导致hh:mm:ss

I am facing some difficulty with calculating the time difference between two dates.

我在计算两个日期之间的时差时遇到了一些困难。

What I want is, I have two dates let say

我想要的是，我有两个约会可以说

@StartDate = '10/01/2012 08:40:18.000'
@EndDate='10/04/2012 09:52:48.000'

so the difference between two dates in the form of hh:mm:ss is 72:42:30.

所以这两个日期在hh:mm:ss是72:42:30。

How can I get this result in a T-SQL query?

如何在T-SQL查询中获得这个结果?

13 个解决方案

#1

declare @StartDate datetime, @EndDate datetime

select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'

select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60)) as [hh:mm:ss]

This query will helpful to you.

这个查询将对您有所帮助。

#2

The shortest code would be:

最短的代码是:

Select CAST((@EndDateTime-@StartDateTime) as time(0)) '[hh:mm:ss]'

#3

While maybe not the most efficient, this would work:

虽然这可能不是最有效的方法，但它会起作用:

declare @StartDate datetime, @EndDate datetime

select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'

select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60))

if you can run two selects then this would be better because you only do the datediff once:

如果您可以运行两个select语句，那么这将会更好，因为您只执行一次datediff:

declare @StartDate datetime, @EndDate datetime

select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'
declare @Sec BIGINT

select @Sec = DateDiff(s, @startDate, @EndDate)

select convert(varchar(5),@sec/3600)+':'+convert(varchar(5),@sec%3600/60)+':'+convert(varchar(5),(@sec%60))

#4

If you're not opposed to implicit type casting I'll offer this an alternative solution. Is it more readable with better formatting? You be the judge.

如果您不反对隐式类型强制转换，我将为您提供另一种解决方案。用更好的格式更容易阅读吗?你是法官。

DECLARE  @StartDate datetime = '10/01/2012 08:40:18.000'
        ,@EndDate   datetime = '10/04/2012 09:52:48.000'

SELECT
    STR(ss/3600, 5) + ':' + RIGHT('0' + LTRIM(ss%3600/60), 2) + ':' + RIGHT('0' + LTRIM(ss%60), 2) AS [hh:mm:ss]
FROM (VALUES(DATEDIFF(s, @StartDate, @EndDate))) seconds (ss)

#5

DECLARE @dt1 datetime='2012/06/13 08:11:12', @dt2 datetime='2012/06/12 02:11:12'

SELECT CAST((@dt2-@dt1) as time(0))

#6

I like the idea of making this into a function so it becomes re-useable and your queries become much easier to read:

我喜欢把它变成一个函数，这样它就变成了可重用的，你的查询变得更容易阅读:

--get the difference between two datetimes in the format: 'h:m:s'
CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME)
RETURNS VARCHAR(10)
AS BEGIN
    DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate)
    DECLARE @difference VARCHAR(10) =
    CONVERT(VARCHAR(4), @seconds / 3600) + ':' +
    CONVERT(VARCHAR(2), @seconds % 3600 / 60) + ':' +
    CONVERT(VARCHAR(2), @seconds % 60)
    RETURN @difference
END

Usage:

用法:

DECLARE @StartDate DATETIME = '10/01/2012 08:40:18.000'
DECLARE @endDate DATETIME = '10/04/2012 09:52:48.000'

SELECT dbo.getDateDiff(@startDate, @endDate) AS DateDifference

Result:

结果:

    DateDifference
1   73:12:30

It's also easier to read the result if you add padding so the format is always hh:mm:ss. For example, here's how you would do that in SQL Server 2012 or later:

如果你添加了填充，也更容易读取结果，所以格式总是hh:mm:ss。例如，在SQL Server 2012或以后的版本中，您可以这样做:

--get the difference between two datetimes in the format: 'hh:mm:ss'
CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME)
RETURNS VARCHAR(10)
AS BEGIN
    DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate)
    DECLARE @difference VARCHAR(10) =
    FORMAT(@seconds / 3600), '00') + ':' +
    FORMAT(@seconds % 3600 / 60, '00') + ':' +
    FORMAT(@seconds % 60, '00')
    RETURN @difference
END

Note that this will not clip the hour if it is more than 2 digits long. So 1 hour would show up as 01:00:00 and 100 hours would show up as 100:00:00

注意，如果一个小时的长度超过两位数，它将不会被裁剪。1小时显示为01:00:00 100小时显示为100:00:00

#7

Take a look at these. I didn't use more parenthesis to keep it readable, so remember that multiplication is done before addition or subtraction.

看看这些。我没有使用更多的括号来保持可读性，所以请记住乘法运算是在加减法之前完成的。

Both below return:

下面两个返回:

hr  mins  sec   timediff
73   12    30   73:12:30

This is written to not use a sub-query and be the most readable and understandable:

这是为了不使用子查询和最可读和可理解:

declare @StartDate datetime,
@EndDate datetime

set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate =   '10/04/2012 09:52:48.000' 

select datediff(hour, @StartDate, @EndDate) hr,
   datediff(minute, @StartDate, @EndDate) 
   - datediff(hour, @StartDate, @EndDate) * 60 mins,
   datediff(second, @StartDate, @EndDate) 
   - (datediff(minute, @StartDate, @EndDate) * 60) sec,
   cast(datediff(hour, @StartDate, @EndDate) as varchar)+':'+ 
   cast(datediff(minute, @StartDate, @EndDate) 
   - datediff(hour, @StartDate, @EndDate) * 60 as varchar)+':'+ 
   cast(datediff(second, @StartDate, @EndDate) 
   - (datediff(minute, @StartDate, @EndDate) * 60) as varchar) timediff

This is a version that would perform better if you have a lot of data. It requires a sub-query.

如果您有大量的数据，这个版本的性能会更好。它需要一个子查询。

declare @StartDate datetime,
@EndDate datetime

set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate =   '10/04/2012 09:52:48.000' 

select s.seconds / 3600  hrs,
s.seconds / 60 - (seconds / 3600 ) * 60 mins,
s.seconds - (s.seconds / 60) * 60   seconds,
cast(s.seconds / 3600 as varchar) + ':' +
cast((s.seconds / 60 - (seconds / 3600 ) * 60) as varchar) + ':' +
cast((s.seconds - (s.seconds / 60) * 60) as varchar) timediff
from (select datediff(second, @StartDate, @EndDate) as seconds) s

#8

I came across this post today as I was trying to gather the time difference between fields located in separate tables joined together on a key field. This is the working code for such an endeavor. (tested in sql 2010) Bare in mind that my original query co-joined 6 tables on a common keyfield, in the code below I have removed the other tables as to not cause any confusion for the reader.

我今天偶然看到这篇文章，因为我试图收集位于不同表中的字段之间的时间差异，这些字段在一个关键字段上连接在一起。这是这样的工作代码。(在sql 2010中进行了测试)注意到，我的原始查询在一个通用的关键字段上与6个表联合，在下面的代码中，我删除了其他表，以免引起读者的混淆。

The purpose of the query is to calculate the difference between the variables CreatedUTC & BackupUTC, where difference is expressed in days and the field is called 'DaysActive.'

查询的目的是计算CreatedUTC和BackupUTC变量之间的差异，其中差异以天数表示，字段称为“DaysActive”。

declare @CreatedUTC datetime
declare @BackupUtc datetime


SELECT TOP 500

table02.Column_CreatedUTC AS DeviceCreated,
CAST(DATEDIFF(day, table02.Column_CreatedUTC, table03.Column_EndDateUTC) AS nvarchar(5))+ ' Days' As DaysActive,
table03.Column_EndDateUTC AS LastCompleteBackup

FROM

Operations.table01 AS table01

LEFT OUTER JOIN

    dbo.table02 AS table02
ON
    table02.Column_KeyField = table01.Column_KeyField

LEFT OUTER JOIN 

    dbo.table03 AS table03
ON
    table01.Column_KeyField = table03.Column_KeyField

Where table03.Column_EndDateUTC > dateadd(hour, -24, getutcdate()) --Gathers records with an end date in the last 24 hours
AND table02.[Column_CreatedUTC] = COALESCE(@CreatedUTC, table02.[Column_CreatedUTC])
AND table03.[Column_EndDateUTC] = COALESCE(@BackupUTC, table03.[Column_EndDateUTC])

GROUP BY table03.Column_EndDateUTC, table02.Column_CreatedUTC
ORDER BY table02.Column_CreatedUTC ASC, DaysActive, table03.Column_EndDateUTC DESC

The Output will be as follows:

输出如下:

[DeviceCreated]..[DaysActive]..[LastCompleteBackup]
---------------------------------------------------------
[2/13/12 16:04]..[463 Days]....[5/21/13 12:14]
[2/12/13 22:37]..[97 Days].....[5/20/13 22:10]

#9

It's A Script Write Copy then write in your script file and change your requered field and get out put

它是一个脚本编写的副本，然后在你的脚本文件中写入，并改变你的请求字段，然后退出。

DECLARE @Sdate DATETIME, @Edate DATETIME, @Timediff VARCHAR(100)
SELECT @Sdate = '02/12/2014 08:40:18.000',@Edate='02/13/2014 09:52:48.000'
SET @Timediff=DATEDIFF(s, @Sdate, @Edate)
SELECT CONVERT(VARCHAR(5),@Timediff/3600)+':'+convert(varchar(5),@Timediff%3600/60)+':'+convert(varchar(5),@Timediff%60) AS TimeDiff

#10

DECLARE  @StartDate datetime = '10/01/2012 08:40:18.000'
        ,@EndDate   datetime = '10/10/2012 09:52:48.000'
        ,@DaysDifferent int = 0
        ,@Sec BIGINT

select @Sec = DateDiff(s, @StartDate, @EndDate)

IF (DATEDIFF(day, @StartDate, @EndDate) > 0)
    BEGIN
        select @DaysDifferent = DATEDIFF(day, @StartDate, @EndDate)
        select @Sec = @Sec - ( @DaysDifferent * 86400 )
        SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss]
    END
ELSE
    BEGIN
        SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss]
    END

----------------------------------------------------------------------------------
dd HH:MM:SS
9d 1:12:30

#11

declare @StartDate datetime, @EndDate datetime

select @StartDate = '2016-05-04 10:23:41.083',@EndDate='2016-05-04 10:25:26.053'

select CAST(DateDiff(MI, @startDate, @EndDate)/60 AS varchar)+':'+Cast(DateDiff(MI, @startDate, @EndDate)%60 AS varchar)+':'+cast(DateDiff(s, @startDate, @EndDate)%60 AS varchar) as [hh:mm:ss]

this will help you too

这对你也有帮助

#12

declare @StartDate datetime, @EndDate datetime

声明@StartDate datetime， @EndDate datetime

set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate =   '10/04/2012 09:52:48.000'

SELECT CONVERT(CHAR(8), CAST(CONVERT(varchar(23),@EndDate,121) AS DATETIME)
-CAST(CONVERT(varchar(23),@StartDate,121)AS DATETIME),8) AS TimeDiff

#13

declare @StartDate datetime;
declare @EndDate datetime;
select @StartDate = '10/01/2012 08:40:18.000';
select @EndDate='10/04/2012 09:52:48.000';
select  cast(datediff(hour,@StartDate,@EndDate) as varchar(10)) + left(right(cast(cast(cast((@EndDate-@StartDate) as datetime) as time) as varchar(16)),14),6)