C语言中给main函数传递参数!

时间:2021-05-04 21:29:46

        相信大家用C语言定义main函数时,大多数人的写法都是int main(void)。其实main函数是可以向其传递参数的,给个实例:

//给main函数传参实例:

#include <stdio.h>
#include <string.h>

//int main(int argc, char *argv[])
int main(int argc, char **argv)
{
    char *array[3]  = {"./main", "hello", "world"};       

    if (argc < 2)
    {  
        printf("error!\n");
        printf("./main str\n");
 
        return -1;
    }

    printf("The first string of your command is:%s\n", argv[0]);
    printf("The second string of your command is:%s\n", argv[1]);
    printf("The third string of your command is:%s\n", argv[2]);
   
    if (!strcmp(argv[0], array[0]))
    {
        printf("The first command execute successfully!\n");   
    }
    if (!strcmp(argv[1], array[1]))
    {
        printf("The second command execute successfully!\n");   
    }
    if (!strcmp(argv[2], array[2]))
    {
        printf("The third command execute successfully!\n");
    }

    return 0;
 }

输出结果:
(1)若输入命令为:./main
     则输出结果为:
     error!
     The command is:./main
(2)若输入命令为:./main hello world
     则输出结果为:
     The first string of your command is:./main
     The second string of your command is:hello
     The third string of your command is:world

     The first command execute successfully!
     The second command execute successfully!
     The third command execute successfully!

        大家可以利用这个程序模型干很多事呢!