题目传送门
/*
贪心:按照0或1开头,若不符合,选择后面最近的进行交换。然后选取最少的交换次数
*/
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <string>
#include <cmath>
#include <vector>
#include <map>
#include <queue>
using namespace std;
const int MAXN = + ;
const int INF = 0x3f3f3f3f;
int a[MAXN], b[MAXN], c[MAXN];
int main(void) //UVALive 6832 Bit String Reordering
{
// freopen ("A.in", "r", stdin);
int n, m;
while (scanf ("%d%d", &n, &m) == )
{
for (int i=; i<=n; ++i) {scanf ("%d", &a[i]); c[i] = a[i];}
for (int i=; i<=m; ++i) scanf ("%d", &b[i]);
int cnt1 = , cnt2 = ; int now = ; int p = ;
bool ok1 = true, ok2 = true;
for (int i=; i<=m && ok1; ++i)
{
for (int j=; j<=b[i]; ++j)
{
if (a[p+j] != now)
{
int k = p + j;
while (k <= n && a[k] != now) k++;
if (k == n+ || a[k] != now) {ok1 = false; break;}
cnt1 += k - (p + j);
swap (a[k], a[p+j]);
}
}
p += b[i]; now = - now;
}
now = ; p = ;
for (int i=; i<=m && ok2; ++i)
{
for (int j=; j<=b[i]; ++j)
{
if (c[p+j] != now)
{
int k = p + j;
while (k <= n && c[k] != now) k++;
if (k == n+ || c[k] != now) {ok2 = false; break;}
cnt2 += k - (p + j);
swap (c[p+j], c[k]);
}
}
p += b[i]; now = - now;
}
// printf ("%d %d\n", cnt1, cnt2);
if (!ok1) printf ("%d\n", cnt2);
else if (!ok2) printf ("%d\n", cnt1);
else printf ("%d\n", min (cnt1, cnt2));
}
return ;
}