如何使用java apache poi从xlsx文件的特定单元格获取值

i am writing a java program to read an excel sheet (xlsx) using apache poi. I can be able to iterate over all the cells and get all the values. But i am not able to get a specific cell value, say E10. Is there any way to find this?

我正在编写一个java程序来使用apache poi读取excel表（xlsx）。我可以遍历所有单元格并获取所有值。但E10说，我无法获得特定的细胞价值。有没有办法找到这个？

Please see the code that i used for iterating over all cells.

请参阅我用于迭代所有单元格的代码。

package application;

import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.Iterator;

import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;

import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;

public class ReadFromXLSX {
    public static void readXLSXFile() throws IOException
    {
        InputStream ExcelFileToRead = new FileInputStream("C:\\Test.xlsx");
        XSSFWorkbook  wb = new XSSFWorkbook(ExcelFileToRead);
        XSSFWorkbook test = new XSSFWorkbook(); 
        XSSFSheet sheet = wb.getSheetAt(0);
        XSSFRow row; 
        XSSFCell cell;
        Iterator rows = sheet.rowIterator();
        while (rows.hasNext())
        {
            row=(XSSFRow) rows.next();
            Iterator cells = row.cellIterator();
            while (cells.hasNext())
            {
                cell=(XSSFCell) cells.next();   
                if (cell.getCellType() == XSSFCell.CELL_TYPE_STRING)
                {
                    System.out.print(cell.getStringCellValue()+" ");
                }
                else if(cell.getCellType() == XSSFCell.CELL_TYPE_NUMERIC)
                {
                    System.out.print(cell.getNumericCellValue()+" ");
                }
                else
                {
                }
            }
            System.out.println();
        }
    }   
}

5 个解决方案

#1

For example, to get E10 of the first worksheet:

例如，要获取第一个工作表的E10：

wb.getSheetAt(0).getRow(9).getCell(4);

Note: subtract one because the indices are null-based.

注意：减去一，因为索引是基于空的。

You can also use this convenience method to map E to 4.

您也可以使用此便捷方法将E映射到4。

wb.getSheetAt(0).getRow(9).getCell(CellReference.convertColStringToIndex("E"));

#2

XSSFSheet has the method getRow(int rownum) It returns the logical row ( 0-based). If you ask for a row that is not defined you get a null. This is to say row 4 represents the fifth row on a sheet.

XSSFSheet的方法是getRow（int rownum）它返回逻辑行（从0开始）。如果您要求未定义的行，则会得到null。这就是说第4行代表工作表上的第五行。

Once you get the row, you can call getCell(int cellnum) method of XSSFRow object. It returns the cell at the given (0 based) index.

获得行后，可以调用XSSFRow对象的getCell（int cellnum）方法。它返回给定（基于0）索引的单元格。

#3

public class XmlFileRead {

public static void main(String[] args) throws IOException {
    FileInputStream fi = new FileInputStream("abc.xls");
    ArrayList<EmployeeVo> al = new ArrayList<>();
    EmployeeVo evo = null;
    Scanner scanner = null;

    Workbook wb = new XSSFWorkbook(fi);
    Sheet sh = wb.getSheet("Sheet0");
    int starRow = sh.getFirstRowNum();
    int endRow = sh.getLastRowNum();

    for (int i = starRow + 1; i < endRow; i++) {
        scanner = new Scanner(System.in);
        evo = new EmployeeVo();
        Cell c = wb.getSheetAt(0).getRow(i).getCell(1);
        evo.setEmployeeId((int) c.getNumericCellValue());

        Cell c2 = wb.getSheetAt(0).getRow(i).getCell(2);
        evo.setEmployeeName(c2.toString());
        // add to collection
        al.add(evo);
    } // for

    al.forEach(i -> {
        System.out.println(i.getEmployeeId() + " " + i.getEmployeeName());
    });

}
}

#4

To get a value from a specific cell in excel you can use the below code line.

要从excel中的特定单元格获取值，可以使用以下代码行。

wb.getSheetAt(0).getRow(1).getCell(1);

#5

Just version-up the getCell method

只需对getCell方法进行版本升级

public XSSFCell getCell(string cellName){
    Pattern r = Pattern.compile("^([A-Z]+)([0-9]+)$");
    Matcher m = r.matcher(cellName);
    if(m.matches()) {
        columnName = m.group(1);
        rowNumber = Integer.parseInt(m.group(2));
        if(rowNumber > 0) {
            return wb.getSheetAt(0).getRow(rowNumber-1).getCell(CellReference.convertColStringToIndex(columnName))
        }
    }
    // throw an exception or return a null
}

Now you can get the cell easily by this line

现在，您可以通过此行轻松获取单元格

getCell("E10")

#1