I'd like to make a regex that matches anything that is succeeded by four points or more:
我想制作一个匹配任何由四点或更多点成功的东西的正则表达式:
asdf.......
Would match to asdf.
会匹配asdf。
I've tried with:
我尝试过:
.+?(?=\.{4,})
but it only discards the last four dots, so it matches asdf....
但它只丢弃最后四个点,所以它匹配asdf ....
How can it be done?
如何做呢?
2 个解决方案
#1
3
The .+?(?=\.{4,}) regex matches asdf in asdf....... since it finds 4 or more dots right after the value, but since the \.{4,} is inside a non-consuming pattern, the ....... remains to be checked and the first . in that substring is matched again since .+? matches any 1 or more chars other than line break chars, but as few as possible. Same happens with the second and third .s since they all are followed with 4+ commas.
。+?(?= \。{4,})正则表达式在asdf .......中匹配asdf,因为它在值后面找到4个或更多点,但是因为\。{4,}位于a非消费模式,.......仍有待检查和第一个。在那个子串中再次匹配。+?匹配除换行符之外的任何1个或多个字符,但尽可能少。同样的情况发生在第二个和第三个.s,因为它们都跟着4个以上的逗号。
What you may do is either make the dot matching part consuming and capture the .+? (then the value you need will be in Group 1):
您可能要做的是使点匹配部分消耗并捕获。+? (那么您需要的值将在第1组中):
(.+?)\.{4,}
See the regex demo
请参阅正则表达式演示
Here, (.*?) is a capturing group matching 0+ chars (use * instead of + to match 1 or more) other than line break chars and \.{4,} will match and consuming 4 or more . chars (not allowing to check for a match when inside the dots).
这里,(。*?)是一个捕获组,匹配0+字符(使用*而不是+匹配1或更多)除了换行符和\。{4,}将匹配并消耗4或更多。 chars(不允许在点内部检查匹配)。
#2
0
^(?!\.+)(.+?)\.{4,}$
Captures anything preceding 4 or more dots, but also makes sure that the string isn't all dots
捕获4个或更多点之前的任何内容,但也确保该字符串不是所有点
If you're searching through a larger document:
如果您正在搜索更大的文档:
(?!\.).+?(?<!\.)(?=\.{4,})
See here for the first example
请参阅此处的第一个示例
See here for the second example
请参阅此处以获取第二个示例
#1
3
The .+?(?=\.{4,}) regex matches asdf in asdf....... since it finds 4 or more dots right after the value, but since the \.{4,} is inside a non-consuming pattern, the ....... remains to be checked and the first . in that substring is matched again since .+? matches any 1 or more chars other than line break chars, but as few as possible. Same happens with the second and third .s since they all are followed with 4+ commas.
。+?(?= \。{4,})正则表达式在asdf .......中匹配asdf,因为它在值后面找到4个或更多点,但是因为\。{4,}位于a非消费模式,.......仍有待检查和第一个。在那个子串中再次匹配。+?匹配除换行符之外的任何1个或多个字符,但尽可能少。同样的情况发生在第二个和第三个.s,因为它们都跟着4个以上的逗号。
What you may do is either make the dot matching part consuming and capture the .+? (then the value you need will be in Group 1):
您可能要做的是使点匹配部分消耗并捕获。+? (那么您需要的值将在第1组中):
(.+?)\.{4,}
See the regex demo
请参阅正则表达式演示
Here, (.*?) is a capturing group matching 0+ chars (use * instead of + to match 1 or more) other than line break chars and \.{4,} will match and consuming 4 or more . chars (not allowing to check for a match when inside the dots).
这里,(。*?)是一个捕获组,匹配0+字符(使用*而不是+匹配1或更多)除了换行符和\。{4,}将匹配并消耗4或更多。 chars(不允许在点内部检查匹配)。
#2
0
^(?!\.+)(.+?)\.{4,}$
Captures anything preceding 4 or more dots, but also makes sure that the string isn't all dots
捕获4个或更多点之前的任何内容,但也确保该字符串不是所有点
If you're searching through a larger document:
如果您正在搜索更大的文档:
(?!\.).+?(?<!\.)(?=\.{4,})
See here for the first example
请参阅此处的第一个示例
See here for the second example
请参阅此处以获取第二个示例