How to generate 25 digit license key using java program.how to convert the given string into 25 digit license key using encoding and decoding formats.
如何使用java program.how生成25位数的许可证密钥,使用编码和解码格式将给定的字符串转换为25位数的许可证密钥。
I use the following code .but it will give first seven digits in license key as AAAAAAA then the license key will change after that first seven digits.how can I get various license keys?
我使用以下代码。但它会将许可证密钥的前七位数字作为AAAAAAA,然后许可证密钥将在前七位数后更改。我可以获得各种许可证密钥吗?
private String charset = "ABCDEFGHJKLMNPQRSTUVWXYZ123456789";
private char[] charArray;
// Random generator = new Random();
private byte[] passwd;
public String Generate(String password)
{
passwd = toByteArray(password);
charArray = strToChar(charset);
byte[] data = new byte[15];
//generator.nextBytes(data);
byte[] tohash = new byte[5+ passwd.length];
//System.arraycopy(data, 0, tohash, 0, 5);
System.arraycopy(passwd, 0, tohash, 5, passwd.length);
try {
byte[] hash = getHash(tohash);
System.arraycopy(hash, 0, data, 5, 10);
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
int num=0;//17
for (int i = 0; i < tohash.length; i++) num += tohash[i];
String serial = Encode(data) + charArray[num & 31];
String ret = "";
for (int i = 0; i < 5; i++)
{
ret += serial.substring((i*5),(i*5)+5);
if (i < 4) ret += "-";
}
return ret;
}
private String Encode(byte[] data){
String ret="" ;
for (int i = 0; i < data.length; i += 5){
ret += charArray[data[i] >> 3 & 0x1f];
ret += charArray[(data[i] << 2 | data[i + 1] >> 6) & 0x1f];
ret += charArray[(data[i + 1] >> 1) & 0x1f];
ret += charArray[(data[i + 1] << 4 | data[i + 2] >> 4) & 0x1f];
ret += charArray[(data[i + 2] << 1 | data[i + 3] >> 7) & 0x1f];
ret += charArray[data[i + 3] >> 2 & 0x1f];
ret += charArray[(data[i + 3] << 3 | data[i + 4] >> 5) & 0x1f];
ret += charArray[data[i + 4] & 0x1f];
//
System.out.println(ret);
}
return ret;
}
private byte[] Decode(String serial){
char[] x = strToChar(serial);
byte[] table = new byte[256];
for (int i = 0; i < charArray.length; i++)
{
table[charArray[i]] = (byte)i;
}
byte[] ret = new byte[x.length * 5 / 8];
int pos = 0;
for (int i = 0; i <= x.length - 8; )
{
byte b1 = table[x[i++]];
byte b2 = table[x[i++]];
byte b3 = table[x[i++]];
byte b4 = table[x[i++]];
byte b5 = table[x[i++]];
byte b6 = table[x[i++]];
byte b7 = table[x[i++]];
byte b8 = table[x[i++]];
ret[pos++] = (byte)(b1 << 3 | b2 >> 2);
ret[pos++] = (byte)(b2 << 6 | b3 << 1 | b4 >> 4);
ret[pos++] = (byte)(b4 << 4 | b5 >> 1);
ret[pos++] = (byte)(b5 << 7 | b6 << 2 | b7 >> 3);
ret[pos++] = (byte)(b7 << 5 | b8);
}
return ret;
}
public int byteArrayToInt(byte[] b, int offset) {
int value = 0;
for (int i = 0; i < 4; i++) {
int shift = (4 - 1 - i) * 8;
value += (b[i + offset] & 0x000000FF) << shift;
}
return value;
}
private char[] strToChar(String str){
char[] c = str.toCharArray();
return c;
}
public byte[] toByteArray(String p) {
String stringToConvert = p;
byte[] theByteArray = stringToConvert.getBytes();
return theByteArray;
}
public byte[] getHash(byte[] toHash) throws NoSuchAlgorithmException, UnsupportedEncodingException {
MessageDigest digest = MessageDigest.getInstance("SHA-256");
digest.reset();
return digest.digest(toHash);
}
1 个解决方案
#1
2
Try this:
try {
byte[] hash = getHash(tohash);
System.arraycopy(hash, 0, data, 0, 15);
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
When you copy like:
当您复制时:
System.arraycopy(hash, 0, data, 5, 10);
Fisrt 5 bytes was == 0;
Fisrt 5个字节= = 0;
#1
2
Try this:
try {
byte[] hash = getHash(tohash);
System.arraycopy(hash, 0, data, 0, 15);
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
When you copy like:
当您复制时:
System.arraycopy(hash, 0, data, 5, 10);
Fisrt 5 bytes was == 0;
Fisrt 5个字节= = 0;