将JSON数据传递给Spring MVC控制器

I need to send a JSON string to Spring MVC controller.But I do not have any form bindings to it , I just need to send a plain JSON data to Controller class.I am making jQuery AJAX call to the Controller method like the below code.

我需要向Spring MVC控制器发送一个JSON字符串。但是我没有任何表单绑定到它，我只需要向Controller类发送一个纯JSON数据。我正在对Controller方法进行jQuery AJAX调用，如下面的代码所示。

$.ajax ({
    url: "./save",
    type: "POST",
    data: JSON.stringify(array),
    dataType: "json",
    contentType: "application/json; charset=utf-8",
    success: function(){
        alert("success ");
    }
});

But how do I retrieve it in the Controller method?(Note: It is just plain JSON data and not a form submission).

但是如何在Controller方法中检索它呢?(注意:它只是纯JSON数据，而不是表单提交)。

3 个解决方案

#1

Add the following dependencies

添加下面的附件

<dependency>
    <groupId>org.codehaus.jackson</groupId> 
    <artifactId>jackson-mapper-asl</artifactId>
    <version>1.9.7</version>
</dependency>

<dependency>
    <groupId>org.codehaus.jackson</groupId> 
    <artifactId>jackson-core-asl</artifactId>
    <version>1.9.7</version>
</dependency>

Modify request as follows

修改请求如下

$.ajax({ 
    url:urlName,    
    type:"POST", 
    contentType: "application/json; charset=utf-8",
    data: jsonString, //Stringified Json Object
    async: false,    //Cross-domain requests and dataType: "jsonp" requests do not support synchronous operation
    cache: false,    //This will force requested pages not to be cached by the browser          
    processData:false, //To avoid making query String instead of JSON
    success: function(resposeJsonObject){
        // Success Message Handler
    }
});

Controller side

控制器端

@RequestMapping(value = urlPattern , method = RequestMethod.POST)
public @ResponseBody Person save(@RequestBody Person jsonString) {

   Person person=personService.savedata(jsonString);
   return person;
}

@RequestBody - Covert Json object to java
@ResponseBody- convert Java object to json

@RequestBody—将Json对象转换为java @ResponseBody—将java对象转换为Json

#2

Html

Html

$('#save').click(function(event) {        
    var jenis = $('#jenis').val();
    var model = $('#model').val();
    var harga = $('#harga').val();
    var json = { "jenis" : jenis, "model" : model, "harga": harga};
    $.ajax({
        url: 'phone/save',
        data: JSON.stringify(json),
        type: "POST",           
        beforeSend: function(xhr) {
            xhr.setRequestHeader("Accept", "application/json");
            xhr.setRequestHeader("Content-Type", "application/json");
        },
        success: function(data){ 
            alert(data);
        }
    });

    event.preventDefault();
});

Controller

控制器

@Controller
@RequestMapping(value="/phone")
public class phoneController {

    phoneDao pd=new phoneDao();

    @RequestMapping(value="/save",method=RequestMethod.POST)
    public @ResponseBody
    int save(@RequestBody Smartphones phone)
    {
        return pd.save(phone);
    }

Dao

刀

public Integer save(Smartphones i) {
    int id = 0;
    Session session=HibernateUtil.getSessionFactory().openSession();
    Transaction trans=session.beginTransaction();
    try {
        session.save(i);   
        id=i.getId();
        trans.commit();
    }
    catch(HibernateException he){}
    return id;
}

#3

You can stringify the JSON Object with JSON.stringify(jsonObject) and receive it on controller as String.

可以使用JSON.stringify(jsonObject)对JSON对象进行stringify，并将其作为String在控制器上接收。

In the Controller, you can use the javax.json to convert and manipulate this.

在控制器中，可以使用javax。json用于转换和操作。

Download and add the .jar to the project libs and import the JsonObject.

下载并将.jar添加到项目libs并导入JsonObject。

To create an json object, you can use

要创建json对象，可以使用

JsonObjectBuilder job = Json.createObjectBuilder();
job.add("header1", foo1);
job.add("header2", foo2);
JsonObject json = job.build();

To read it from String, you can use

要从字符串中读取它，可以使用

JsonReader jr = Json.createReader(new StringReader(jsonString));
JsonObject json = jsonReader.readObject();
jsonReader.close();

#1