I am trying to send JSON to a Spring MVC Controller. On the Spring MVC side, everything is configured correctly.
我尝试将JSON发送给Spring MVC控制器。在Spring MVC端,一切都被正确配置。
Below is the code but doesn't seem to run:
下面是代码,但似乎没有运行:
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
$('#myForm').on('submit', function(e) {
e.preventDefault();
var frm = $("#myForm");
var dat = frm.serialize();
$.ajax({
type: 'POST',
url: $('#myForm').attr('action'),
data: dat,
contentType: 'application/json'
success: function(hxr) {
alert("Success: " + xhr);
}
});
});
</script>
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/save" method="POST" accept="application/json" onclick="i()">
<input type="text" name="name" value="myName">
<input type="submit" value="Submit">
</form>
In Tomcat I get the following error:
在Tomcat中,我得到以下错误:
org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod WARNING: No matching handler method found for servlet request: path '/application/save', method 'POST', parameters map['name' -> array['myName']]
org.springframework.web.servlet.mvc.support。DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod警告:没有为servlet请求找到匹配的处理程序方法:path '/application/save',方法'POST',参数映射['name' ->数组['myName']]
Any ideas where I am going wrong? I am new to JSON. I am trying to to send JSON to Spring MVC controller.
你知道我哪里出错了吗?我对JSON很陌生。我正在尝试向Spring MVC控制器发送JSON。
@Controller
@RequestMapping("/run/*")
public class HistoryController {
@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody Response save(@RequestBody User user) throws Exception {
Response userResponse = new Response();
System.out.println("UserId :" + " " + user.getName());
return userResponse;
}
}
@RequestMapping(value = "find", method = RequestMethod.GET)
public @ResponseBody Response find() {
System.out.println("Run");
Response userResponse = new Response();
userResponse.setVersionNumber("1.0");
return userResponse;
}
When invoking /application/run/save I get a JSON response. However the @RequestBody does not work.
当调用/应用程序/运行/保存时,我得到一个JSON响应。但是@RequestBody不能工作。
I still have had no luck. Have read some many similiar problems. The requirement is that the server will only accept application/json types. I am using a Spring MVC Controller. As mentioned earlier, the code sends a response back as JSON through @ResponseBody. I want to get information through the @RequestBody in my Spring MVC Controller. I am using JSP to send JSON to Spring MVC Controller. My code and Spring MVC can be seen below:
我仍然没有运气。读过许多相似的问题。要求是服务器只接受应用程序/json类型。我使用的是Spring MVC控制器。如前所述,代码通过@ResponseBody以JSON形式返回响应。我想通过Spring MVC控制器中的@RequestBody获取信息。我正在使用JSP将JSON发送给Spring MVC控制器。我的代码和Spring MVC如下:
I am new to JSON and Javascript.
我是JSON和Javascript的新手。
JSP - index.jsp
JSP - index . JSP
<%@page language="java" contentType="text/html"%>
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
$('#myForm').on('submit', function(e) {
var frm = $("#myForm");
var dat = JSON.stringify(frm.serializeArray());
$.ajax({
type: 'POST',
url: $('#myForm').attr('action'),
data: dat,
contentType: 'application/json',
dataType: 'json',
error: function() {
alert('failure');
}
success: function(hxr) {
alert("Success: " + xhr);
}
});
);
};
</script>
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/save" method="POST" accept="application/json" onclick="i()">
<input type="text" name="userId" value="User">
<input type="submit" value="Submit">
</form>
</body>
</html>
When running this I am not getting any output. In the Chrome I get 404 Not found error and in Tomcat I get the following error:
运行时,我不会得到任何输出。在Chrome中我得到404未发现错误,在Tomcat中我得到以下错误:
org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/application/sa
ve', method 'POST', parameters map['userId' -> array<String>['User']]
Is something wrong here in the JSP part?
JSP部分有问题吗?
web.xml
web . xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd"
version="2.5">
<display-name>WebApp</display-name>
<context-param>
<!-- Specifies the list of Spring Configuration files in comma separated format.-->
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/service.xml</param-value>
</context-param>
<listener>
<!-- Loads your Configuration Files-->
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>application</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>application</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
service.xml
service . xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.0.xsd">
<context:component-scan base-package="com.web"/>
<mvc:annotation-driven/>
<context:annotation-config/>
<bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/>
<bean id="jacksonMessageChanger" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
<property name="supportedMediaTypes" value="application/json"/>
</bean>
<!-- <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="jacksonMessageChanger"/>
</list>
</property>
</bean>-->
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<util:list id="beanList">
<ref bean="jacksonMessageChanger"/>
</util:list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
<!-- <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
<property name="mediaTypes">
<map>
<entry key="json" value="application/json"/>
</map>
</property>
</bean>-->
</beans>
Controller
控制器
package com.web;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RequestBody;
import com.webchannel.domain.User;
import com.webchannel.domain.UserResponse;
@Controller
@RequestMapping("/application/*")
public class SaveController {
@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody UserResponse save(@RequestBody User user) throws Exception {
UserResponse userResponse = new UserResponse();
System.out.println("UserId :" + " " + user.getUserId());
return userResponse;
}
@RequestMapping(value = "delete", method = RequestMethod.GET)
public @ResponseBody UserResponse delete() {
System.out.println("Delete");
UserResponse userResponse = new UserResponse();
userResponse.setSuccess(true);
userResponse.setVersionNumber("1.0");
return userResponse;
}
}
When invoking /application/delete I get JSON returned. So I know my JacksonProcessor is configured correctly. The problem is in @RequestBody.
调用/应用程序/删除时,返回JSON。我知道我的杰克逊处理器配置正确。问题在@RequestBody中。
Where am I going wrong? Please help me.
我哪里出错了?请帮助我。
4 个解决方案
#1
1
This question is a bit hard to follow since there seems to be a few different problems.
这个问题有点难以理解,因为似乎有几个不同的问题。
But looking just at this problem:
但是看看这个问题
In Tomcat I get the following error:
在Tomcat中,我得到以下错误:
org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod WARNING: No matching handler method found for servlet request: path '/application/run', method 'POST', parameters map['name' -> array['myName']]
org.springframework.web.servlet.mvc.support。DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod警告:没有为servlet请求找到匹配的处理程序方法:path '/application/run',方法'POST',参数映射['name' ->数组['myName']]
In the HTML you posted, you have a <form>
that is set to POST
to /application/run
.
在您发布的HTML中,有一个
However, in your @Controller
class, you do not have any method bound to this URL.
但是,在@Controller类中,没有任何方法绑定到这个URL。
Because you've annotated the class with @RequestMapping("/run/*")
and the method is annotated with @RequestMapping("save")
, the save()
method is actually bound to the URL /run/save
- which is neither the URL you are sending data to with $.ajax()
nor the URL the form is pointing at.
因为您已经用@RequestMapping(“/run/*”)注释了类,并且这个方法也用@RequestMapping(“save”)注释,所以save()方法实际上绑定到URL /run/save——它既不是您用$.ajax()发送数据到的URL,也不是表单指向的URL。
I would suggest turning up logging on the org.springframework.web
loggers to DEBUG
- when your app starts up Spring will log every URL that each method is mapped to.
我建议在org.springframework上登录。web日志记录器要调试——当应用程序启动时,Spring将记录每个方法映射到的每个URL。
#2
1
I think you may need make couple of changes
我想你可能需要做些改变。
-
Since your controller has
@RequestMapping("/run/*")
, you may need to change this to@RequestMapping("/run/")
and in the jsp form action you may need to change<form id="myForm" action="/application/run/save" method="POST" accept="application/json" onclick="i()">
, since you have defined@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
for the 'save` method in the controller.由于您的控制器有@RequestMapping("/run/*"),您可能需要将其更改为@RequestMapping("/run/"),在jsp表单操作中,您可能需要更改
-
You may need to define the @RequestParam in the save method in controller like
public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody User user) throws Exception {...}
您可能需要在控制器的save方法中定义@RequestParam,如public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody用户)抛出异常{…}
Since it clearly says that there is no handler attached to the request you are submitting.
因为它清楚地表明,您提交的请求没有附加处理程序。
#3
0
Try the following
试试以下
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
$('#myForm').on('submit', function(e) {
e.preventDefault();
var frm = $("#myForm");
var dat = frm.serialize();
$.ajax({
type: 'POST',
url: $('#myForm').attr('action'),
data: dat,
contentType: 'application/json'
success: function(hxr) {
alert("Success: " + hxr);
}
});
});
</script>
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/run" method="POST">
<input type="text" name="name" value="myName">
<input type="submit" value="Submit">
</form>
The dataType:'json'
is specifying what the format you are expecting from the server,
dataType:“json”指定了您期望从服务器得到的格式,
And it would be better to assist if you post your handler code.
如果您发布您的处理程序代码,最好提供帮助。
#4
0
There is no method in the controller mapped to your /application/run
. I'm not sure which one you want to call, but to the url
you have to add find
orsave
. Or create a method mapped to /application/run
. Cheers!
控制器中没有映射到您/应用程序/运行的方法。我不确定你要调用哪个,但是你需要在url中添加find或save。或者创建一个映射到/application/run的方法。干杯!
#1
1
This question is a bit hard to follow since there seems to be a few different problems.
这个问题有点难以理解,因为似乎有几个不同的问题。
But looking just at this problem:
但是看看这个问题
In Tomcat I get the following error:
在Tomcat中,我得到以下错误:
org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod WARNING: No matching handler method found for servlet request: path '/application/run', method 'POST', parameters map['name' -> array['myName']]
org.springframework.web.servlet.mvc.support。DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod警告:没有为servlet请求找到匹配的处理程序方法:path '/application/run',方法'POST',参数映射['name' ->数组['myName']]
In the HTML you posted, you have a <form>
that is set to POST
to /application/run
.
在您发布的HTML中,有一个
However, in your @Controller
class, you do not have any method bound to this URL.
但是,在@Controller类中,没有任何方法绑定到这个URL。
Because you've annotated the class with @RequestMapping("/run/*")
and the method is annotated with @RequestMapping("save")
, the save()
method is actually bound to the URL /run/save
- which is neither the URL you are sending data to with $.ajax()
nor the URL the form is pointing at.
因为您已经用@RequestMapping(“/run/*”)注释了类,并且这个方法也用@RequestMapping(“save”)注释,所以save()方法实际上绑定到URL /run/save——它既不是您用$.ajax()发送数据到的URL,也不是表单指向的URL。
I would suggest turning up logging on the org.springframework.web
loggers to DEBUG
- when your app starts up Spring will log every URL that each method is mapped to.
我建议在org.springframework上登录。web日志记录器要调试——当应用程序启动时,Spring将记录每个方法映射到的每个URL。
#2
1
I think you may need make couple of changes
我想你可能需要做些改变。
-
Since your controller has
@RequestMapping("/run/*")
, you may need to change this to@RequestMapping("/run/")
and in the jsp form action you may need to change<form id="myForm" action="/application/run/save" method="POST" accept="application/json" onclick="i()">
, since you have defined@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
for the 'save` method in the controller.由于您的控制器有@RequestMapping("/run/*"),您可能需要将其更改为@RequestMapping("/run/"),在jsp表单操作中,您可能需要更改
-
You may need to define the @RequestParam in the save method in controller like
public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody User user) throws Exception {...}
您可能需要在控制器的save方法中定义@RequestParam,如public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody用户)抛出异常{…}
Since it clearly says that there is no handler attached to the request you are submitting.
因为它清楚地表明,您提交的请求没有附加处理程序。
#3
0
Try the following
试试以下
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
$('#myForm').on('submit', function(e) {
e.preventDefault();
var frm = $("#myForm");
var dat = frm.serialize();
$.ajax({
type: 'POST',
url: $('#myForm').attr('action'),
data: dat,
contentType: 'application/json'
success: function(hxr) {
alert("Success: " + hxr);
}
});
});
</script>
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/run" method="POST">
<input type="text" name="name" value="myName">
<input type="submit" value="Submit">
</form>
The dataType:'json'
is specifying what the format you are expecting from the server,
dataType:“json”指定了您期望从服务器得到的格式,
And it would be better to assist if you post your handler code.
如果您发布您的处理程序代码,最好提供帮助。
#4
0
There is no method in the controller mapped to your /application/run
. I'm not sure which one you want to call, but to the url
you have to add find
orsave
. Or create a method mapped to /application/run
. Cheers!
控制器中没有映射到您/应用程序/运行的方法。我不确定你要调用哪个,但是你需要在url中添加find或save。或者创建一个映射到/application/run的方法。干杯!