Can you solve this equation?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5667 Accepted Submission(s): 2681
http://acm.hdu.edu.cn/showproblem.php?pid=2199
Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2 100 -4
Sample Output
1.6152 No solution!
Author
Redow
Recommend
lcy
二分搜索
代码:
#include<iostream>
#include<cstdio>
#define sum(x) ((8*x*x*x*x)+(7*x*x*x)+(2*x*x)+(3*x)+(6))
using namespace std;
int main()
{
int t;
double y,mid,left,right;
cin>>t;
while(t--)
{
scanf("%lf",&y);
left=0.0,right=100.0;
if(y>=6.0&&y<=sum())
{
while(right-left>1e-)
{
mid=(left+right)/2.0;
if(sum(mid)-y>1e-)
right=mid;
else
if(y-sum(mid)>1e-)
left=mid;
else
break;
}
printf("%.4lf\n",mid);
}
else
puts("No solution!");
}
return ;
}