在另一个Web视图控件中打开超链接

I want to open link in another web view control on clicking the hyperlinks in another web view in swing using Java FX

我想在另一个Web视图控件中打开链接，使用Java FX单击另一个Web视图中的超链接

Actually i am having two web view controls A n B on the same screen . On clicking the hyperlink in a , new link should be opened in B web view control

实际上我在同一个屏幕上有两个Web视图控件A n B.单击a中的超链接时，应在B Web视图控件中打开新链接

1 个解决方案

#1

Allow webviewA to open content in webviewB

允许webviewA在webviewB中打开内容

Use setCreatePopupHandler:

使用setCreatePopupHandler：

webviewA.getEngine().setCreatePopupHandler(new Callback<PopupFeatures, WebEngine>() {
  @Override public WebEngine call(PopupFeatures popupFeatures) {
    return webviewB.getEngine();
  }
});

Or, if you are using jdk8 and don't like typing:

或者，如果您使用的是jdk8并且不喜欢打字：

webviewA.getEngine().setCreatePopupHandler(
  popupFeatures -> webviewB.getEngine()
);

Make your html links open content in a new window

使您的HTML链接在新窗口中打开内容

Define the hyperlinks in the document loaded in webviewA using target="_blank"

使用target =“_ blank”定义webviewA中加载的文档中的超链接

For example:

例如：

webviewA.loadContent(
  "<a href='http://sundae.triumf.ca/pub2/cave/node001.html' target='_blank'>" +
    "XYZZY" +
  "</a>"
);

when you click on the hyperlink and utter the magic word, it will open the Colossal Cave adventure in webviewB.

当你点击超链接并说出神奇的单词时，它将在webviewB中打开Colossal Cave冒险。

#1