看代码看到
public Runnable r = new Runnable()
{
@Override
public void run()
{
...
}
}
接口不能new ,不过可以生成一个匿名类,省略了写一个具体类实现接口的开销。
public class Main { public static void main(String[] args) {
String a=new CustomerImpl().sayHello("hongda");
System.out.println(a);
String b=new Customer(){
public String sayHello(String name){
return "Hello2 "+name;
}
}.sayHello("hongdada");
System.out.println(b); }
} interface Customer {
public String sayHello(String name);
} class CustomerImpl implements Customer {
@Override
public String sayHello(String name) {
return "Hello, " + name;
}
}
Hello, hongda
Hello2 hongdada
如果接口内有多个方法呢?
public class Main { public static void main(String[] args) {
String a=new CustomerImpl().sayHello("hongda");
System.out.println(a);
String b=new Customer(){
public String sayHello(String name){
return "Hello2 "+name;
}
}.sayHello("hongdada");
System.out.println(b); }
} interface Customer {
public String sayHello(String name);
public int Add(int a ,int b);
} class CustomerImpl implements Customer {
@Override
public String sayHello(String name) {
return "Hello, " + name;
}
@Override
public int Add(int a ,int b){
return a+b;
}
}
Error:(8, 32) java: <匿名com.company.Main$1>不是抽象的, 并且未覆盖com.company.Customer中的抽象方法Add(int,int)
匿名类内部实现接口全部方法:
public class Main { public static void main(String[] args) {
String a=new CustomerImpl().sayHello("hongda");
System.out.println(a);
String b=new Customer(){
public String sayHello(String name){
return "Hello2 "+name;
}
public int Add(int a ,int b){
return a+b;
}
}.sayHello("hongdada");
System.out.println(b); }
} interface Customer {
public String sayHello(String name);
public int Add(int a ,int b);
} class CustomerImpl implements Customer {
@Override
public String sayHello(String name) {
return "Hello, " + name;
}
@Override
public int Add(int a ,int b){
return a+b;
}
}
Hello, hongda
Hello2 hongdada
这种实现接口方式其实就是一个实现一个继承接口的匿名类。