比较sql server中两个字符串中的数字

时间:2022-01-09 15:53:53

I am having two strings as @CountryLocationIDs and @LocationIDs with values:

我有两个字符串@ countrylocationid和@ locationid,值为:

@CountryLocationIDs = 400,600,150,850,160,250
@LocationIDs1       = 600,150,900

Then I need the output in another variable as:

然后我需要另一个变量的输出:

@LocationIDs = 400,600,150,850,160,250,900

Anybody please help out... Thanks in advance...

有人请帮忙…提前谢谢…

3 个解决方案

#1


3  

I have created table-valued function which accepts two parameters, first is string with IDs, and second is delimiter in string.

我已经创建了表值函数,它接受两个参数,第一个是带id的字符串,第二个是字符串分隔符。

CREATE FUNCTION [dbo].[Split](@String nvarchar(4000), @Delimiter char(1))       
returns @temptable TABLE (items nvarchar(4000))       
as       
begin       
    declare @idx int       
    declare @slice nvarchar(4000)       

    select @idx = 1       
        if len(@String)<1 or @String is null  return       

    while @idx!= 0       
    begin       
        set @idx = charindex(@Delimiter,@String)       
        if @idx!=0       
            set @slice = left(@String,@idx - 1)       
        else       
            set @slice = @String       

        if(len(@slice)>0)  
            insert into @temptable(Items) values(@slice)       

        set @String = right(@String,len(@String) - @idx)       
        if len(@String) = 0 break       
    end   
return       
end  

After creating function, just use UNION set operator on this way:

创建函数后,使用UNION set操作符:

EDITED

编辑

WITH ListCTE AS 
(
select items from dbo.split('400,600,150,850,160,250', ',')
union
select items from dbo.split('600,150,900', ',')
)
SELECT TOP 1

   MemberList = substring((SELECT ( ', ' + items )
                           FROM ListCTE t2
                           ORDER BY 
                              items
                           FOR XML PATH( '' )
                          ), 3, 1000 )FROM ListCTE t1

With UNION you will automatically get distinct values from both strings, so you don't need to use DISTINCT clause

使用UNION,您将自动从两个字符串中获得不同的值,因此不需要使用不同的子句

#2


3  

Also you can use option with dynamic management function sys.dm_fts_parser
Before script execution you need check full-text component is installed:

还可以使用带有动态管理功能的选项系统。在执行脚本之前,需要检查是否安装了全文本组件:

SELECT FULLTEXTSERVICEPROPERTY ('IsFulltextInstalled')

0 = Full-text is not installed. 1 = Full-text is installed. NULL = Invalid input, or error.

0 =未安装全文。1 =全文安装。NULL =无效输入或错误。

If 0 = Full-text is not installed then this post is necessary to you How to install fulltext on sql server 2008?

如果0 =全文本没有安装,那么这篇文章对于您如何在sql server 2008上安装全文本是必要的。

DECLARE @CountryLocationIDs nvarchar(100) = '400,600,150,850,160,250',
        @LocationIDs1       nvarchar(100) = '600,150,900',
        @LocationIDs        nvarchar(100) = N''

SELECT @LocationIDs += display_term + ','
FROM sys.dm_fts_parser('"'+ 'nn,' + @CountryLocationIDs + ',' + @LocationIDs1 + '"', 1033, NULL, 0)  
WHERE display_term NOT LIKE 'nn%'
GROUP BY display_term

SELECT LEFT(@LocationIDs, LEN(@LocationIDs) - 1)

#3


0  

This will help you through programming

这将通过编程帮助您

and you may also refer this

你也可以参考这个

#1


3  

I have created table-valued function which accepts two parameters, first is string with IDs, and second is delimiter in string.

我已经创建了表值函数,它接受两个参数,第一个是带id的字符串,第二个是字符串分隔符。

CREATE FUNCTION [dbo].[Split](@String nvarchar(4000), @Delimiter char(1))       
returns @temptable TABLE (items nvarchar(4000))       
as       
begin       
    declare @idx int       
    declare @slice nvarchar(4000)       

    select @idx = 1       
        if len(@String)<1 or @String is null  return       

    while @idx!= 0       
    begin       
        set @idx = charindex(@Delimiter,@String)       
        if @idx!=0       
            set @slice = left(@String,@idx - 1)       
        else       
            set @slice = @String       

        if(len(@slice)>0)  
            insert into @temptable(Items) values(@slice)       

        set @String = right(@String,len(@String) - @idx)       
        if len(@String) = 0 break       
    end   
return       
end  

After creating function, just use UNION set operator on this way:

创建函数后,使用UNION set操作符:

EDITED

编辑

WITH ListCTE AS 
(
select items from dbo.split('400,600,150,850,160,250', ',')
union
select items from dbo.split('600,150,900', ',')
)
SELECT TOP 1

   MemberList = substring((SELECT ( ', ' + items )
                           FROM ListCTE t2
                           ORDER BY 
                              items
                           FOR XML PATH( '' )
                          ), 3, 1000 )FROM ListCTE t1

With UNION you will automatically get distinct values from both strings, so you don't need to use DISTINCT clause

使用UNION,您将自动从两个字符串中获得不同的值,因此不需要使用不同的子句

#2


3  

Also you can use option with dynamic management function sys.dm_fts_parser
Before script execution you need check full-text component is installed:

还可以使用带有动态管理功能的选项系统。在执行脚本之前,需要检查是否安装了全文本组件:

SELECT FULLTEXTSERVICEPROPERTY ('IsFulltextInstalled')

0 = Full-text is not installed. 1 = Full-text is installed. NULL = Invalid input, or error.

0 =未安装全文。1 =全文安装。NULL =无效输入或错误。

If 0 = Full-text is not installed then this post is necessary to you How to install fulltext on sql server 2008?

如果0 =全文本没有安装,那么这篇文章对于您如何在sql server 2008上安装全文本是必要的。

DECLARE @CountryLocationIDs nvarchar(100) = '400,600,150,850,160,250',
        @LocationIDs1       nvarchar(100) = '600,150,900',
        @LocationIDs        nvarchar(100) = N''

SELECT @LocationIDs += display_term + ','
FROM sys.dm_fts_parser('"'+ 'nn,' + @CountryLocationIDs + ',' + @LocationIDs1 + '"', 1033, NULL, 0)  
WHERE display_term NOT LIKE 'nn%'
GROUP BY display_term

SELECT LEFT(@LocationIDs, LEN(@LocationIDs) - 1)

#3


0  

This will help you through programming

这将通过编程帮助您

and you may also refer this

你也可以参考这个