In my SQL Server stored procedures I want to do this:
在我的SQL Server存储过程中,我想这样做:
"hello xxx how are you"
where xxx
is a value of a variable
其中xxx是变量的值
I tried this
我试过这个
CREATE PROCEDURE insertToPinTable
(@callerID VARCHAR (200),
@vAccount VARCHAR (200))
AS
BEGIN
DECLARE @textEnglish VARCHAR
textEnglish = CONCAT ( "hello", @vAccount)
INSERT INTO pinData([CallerID], [body], [processed])
VALUES (@callerID, @textEnglish, 0)
END
I get an error
我收到一个错误
Incorrect syntax near 'textEnglish'
'textEnglish'附近的语法不正确
it seems that using CONCAT
is not correct, could you help me please
似乎使用CONCAT是不正确的,你能帮我吗?
(if I can insert the value of vAccount to the hello
word, then in the same way I can insert the value of textEnglish, to the string how are you
)
(如果我可以将vAccount的值插入到hello单词中,那么我可以以相同的方式将textEnglish的值插入到字符串中,你好吗?)
2 个解决方案
#1
4
CREATE PROCEDURE insertToPinTable
(
@callerID VARCHAR (200),
@vAccount VARCHAR (200)
)
AS
BEGIN
DECLARE @textEnglish VARCHAR(255) --missing length previously
set @textEnglish = 'hello'+ @vAccount --missing set keyword
INSERT INTO pinData([CallerID], [body], [processed]) VALUES (@callerID, @textEnglish, 0)
END
#2
0
If you just want to change a string from
如果您只想更改字符串
"hello xxx how are you"
to
至
"hello Mr. Smith how are you"
You might think about place holder replacement:
您可以考虑更换占位符:
Define your string as a template:
将字符串定义为模板:
DECLARE @template VARCHAR(100)='hello {Name} how are you?';
And then use
然后使用
SELECT REPLACE(@template,'{Name}','Mr. Smith');
#1
4
CREATE PROCEDURE insertToPinTable
(
@callerID VARCHAR (200),
@vAccount VARCHAR (200)
)
AS
BEGIN
DECLARE @textEnglish VARCHAR(255) --missing length previously
set @textEnglish = 'hello'+ @vAccount --missing set keyword
INSERT INTO pinData([CallerID], [body], [processed]) VALUES (@callerID, @textEnglish, 0)
END
#2
0
If you just want to change a string from
如果您只想更改字符串
"hello xxx how are you"
to
至
"hello Mr. Smith how are you"
You might think about place holder replacement:
您可以考虑更换占位符:
Define your string as a template:
将字符串定义为模板:
DECLARE @template VARCHAR(100)='hello {Name} how are you?';
And then use
然后使用
SELECT REPLACE(@template,'{Name}','Mr. Smith');