本文实例为大家分享了C++实现走迷宫小游戏的具体代码,供大家参考,具体内容如下
源码下载:C++实现走迷宫小游戏
主程序代码:
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#include<conio.h>
#include<stdlib.h>
#include<time.h>
#include<string.h>
#include<windows.h>
#include<iostream>
using namespace std;
char pr[10]={1, ' ' , 'E' , 'O' } ;
int level,n,m,map[50][50],i,j,x,y,k,ex,ey;
char c[1001];
int main(){
system ( "cls" );
puts ( "if you no full screen,please press full screen" );
getch();
system ( "cls" );
puts ( "please choose level" );
again:;
cin>>level;
if (level>1||level<1){
puts ( "haven't this level" );
goto again;
}
puts ( "loading..." );
sprintf (c, "%d.map" ,level);
freopen (c, "r" ,stdin);
cin>>n>>m;
for (i=1;i<=n;i++)
for (j=1;j<=m;j++)
cin>>map[i][j];
fclose (stdin);
for (i=1;i<=n;i++)
for (j=1;j<=m;j++)
if (map[i][j]==3){
x=i;
y=j;
}
else if (map[i][j]==2){
ex=i;
ey=j;
}
while (x!=ex&&y!=ey){
system ( "cls" );
for (i=1;i<=n;i++, putchar ( '\n' ))
for (j=1;j<=m;j++)
putchar (pr[map[i][j]]);
k=getch();
if (k== 'w' )
if (map[x-1][y]&&(x-1)){
map[x-1][y]=3;
map[x][y]=1;
x--;
}
if (k== 's' )
if (map[x+1][y]&&(x+1)<=n){
map[x+1][y]=3;
map[x][y]=1;
x++;
}
if (k== 'a' )
if (map[x][y-1]&&(y-1)){
map[x][y-1]=3;
map[x][y]=1;
y--;
}
if (k== 'd' )
if (map[x][y+1]&&(y+1)<=m){
map[x][y+1]=3;
map[x][y]=1;
y++;
}
}
system ( "cls" );
return 0;
}
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以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/hh_cnyali/article/details/51916495