Color the Ball
Time Limit: 2 Seconds Memory Limit: 65536 KB
There are infinite balls in a line (numbered 1 2 3 ....), and initially all of them are paint black. Now Jim use a brush paint the balls, every time give two integers a b and follow by a char 'w' or 'b', 'w' denotes the ball from a to b are painted white, 'b' denotes that be painted black. You are ask to find the longest white ball sequence.
Input
First line is an integer N (<=2000), the times Jim paint, next N line contain a b c, c can be 'w' and 'b'.
There are multiple cases, process to the end of file.
Output
Two integers the left end of the longest white ball sequence and
the right end of longest white ball sequence (If more than one output
the small number one). All the input are less than 2^31-1. If no such
sequence exists, output "Oh, my god".
Sample Input
3
1 4 w
8 11 w
3 5 b
Sample Output
8 11
解题思路：n未知，因此离散化好处理，线段树的区间更新
#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <vector>
#include <queue>
#include <cstdlib>
#include <iomanip>
#include <cmath>
#include <ctime>
#include <map>
#include <set>
using namespace std;
#define lowbit(x) (x&(-x))
#define max(x,y) (x>y?x:y)
#define min(x,y) (x<y?x:y)
#define MAX 100000000000000000
#define MOD 1000000007
#define pi acos(-1.0)
#define ei exp(1)
#define PI 3.141592653589793238462
#define INF 0x3f3f3f3f3f
#define mem(a) (memset(a,0,sizeof(a)))
typedef long long ll;
const int maxn=;
struct node
{
int l,r,co;
}tree[maxn*];
int n,cnt,tot;
int num[maxn],ha[maxn],color[maxn],co[maxn],li[maxn],ri[maxn];
int find(int x)
{
int l=,r=cnt;
while(l<=r)
{
int mid=(l+r)>>;
if(ha[mid]==x) return mid;
else if(ha[mid]<x) l=mid+;
else r=mid-;
}
return -;
}
void build(int l,int r,int root)
{
tree[root].l=l,tree[root].r=r,tree[root].co=;
if(l==r) return ;
int mid=(l+r)>>;
build(l,mid,root<<);
build(mid+,r,root<<|);
}
void update(int l,int r,int root,int val)
{
if(tree[root].l==l && tree[root].r==r)
{
tree[root].co=val;
return;
}
if(tree[root].co==val) return;
if(tree[root].co!=-)
{
tree[root<<].co=tree[root<<|].co=tree[root].co;
tree[root].co=-;
}
if(r<=tree[root<<].r) update(l,r,root<<,val);
else if(l>=tree[root<<|].l)update(l,r,root<<|,val);
else update(l,tree[root<<].r,root<<,val),update(tree[root<<|].l,r,root<<|,val);
}
void query(int l,int r,int root)
{
if(tree[root].co!=-)
{
for(int i=tree[root].l;i<=tree[root].r;i++)
color[i]=tree[root].co;
return;
}
if(r<=tree[root<<].r) query(l,r,root<<);
else if(l>=tree[root<<|].l) query(l,r,root<<|);
else query(l,tree[root<<].r,root<<),query(tree[root<<|].l,r,root<<|); }
int main(int argc,char *argv[])
{
char s[];
while(scanf("%d",&n)!=EOF)
{
tot=;
memset(color,,sizeof(color));
for(int i=;i<n;i++)
{
scanf("%d%d%s",&li[i],&ri[i],s);
co[i]=s[]=='b'?:;
num[tot++]=li[i];
num[tot++]=ri[i];
}
sort(num,num+tot);
int t=tot;
for(int i=;i<t;i++)
{
if(num[i]-num[i-]>) num[tot++]=num[i-]+;
if(num[i]-num[i-]>) num[tot++]=num[i]-;
}
sort(num,num+tot);
cnt=;
ha[++cnt]=num[];
for(int i=;i<tot;i++)
if(num[i-]!=num[i]) ha[++cnt]=num[i];
build(,maxn,);
for(int i=;i<n;i++)
{
int a=find(li[i]);
int b=find(ri[i]);
update(a,b,,co[i]);
}
query(,maxn,);
int s,e,ans=,i=,j;
while(i<=cnt)
{
if(color[i]==)
{
j=i;
while(color[j]== && j<=cnt) j++;
int t=ha[j-]-ha[i]+;
if(t>ans)
{
ans=t;
s=ha[i];
e=ha[j-];
}
i=j;
}
else i++;
}
if(!ans) printf("Oh,my god\n");
else printf("%d %d\n",s,e);
}
return ;
}