Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11
(i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
这个问题分为两种情况,一种不可以修改原数组元素,另一种可以修改数组元素
1、可以修改数组元素
class Solution {
public:
int minimumTotal(vector<vector<int>>& triangle) {
for(int i = triangle.size()-; i >= ; --i)
{
for(int j = ; j < i+;++j)
{
if(triangle[i+][j]<triangle[i+][j+])
triangle[i][j] += triangle[i+][j];
else
triangle[i][j] += triangle[i+][j+];
} }
return triangle[][];
}
};
2、不能修改数组元素