用JAVA中BufferedImage画出漂亮的验证码点击变化

如果我们想用JAVA中BufferedImage画出漂亮的验证码点击变化怎么实现呢，类似这样：

点击变化，以下是实现过程，直接上代码：

 首先前台：<i><img style="height:22px;" id="zcodeImg" alt="点击更换" title="点击更换" src="" /></i>放在你页面想展示的位置;接着页面加载时

1 2 3 4 5

$(document).ready(function() { changeCode1(); $("#codeImg").bind("click", changeCode1); }); function changeCode1() { $("#codeImg").attr("src", "code.do?t=" + genTimestamp());//secCodeController }

js部分写完了，现在是控制层，直接上代码：

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59

@Controller @RequestMapping("/code") public class SecCodeController { @RequestMapping public void generate(HttpServletResponse response){ ByteArrayOutputStream output = new ByteArrayOutputStream(); String code = drawImg(output); Subject currentUser = SecurityUtils.getSubject(); Session session = currentUser.getSession(); session.setAttribute(Const.SESSION_SECURITY_CODE, code); try { ServletOutputStream out = response.getOutputStream(); output.writeTo(out); out.close(); } catch (IOException e) { //e.printStackTrace(); } } private String drawImg(ByteArrayOutputStream output){ String code = ""; for(int i=0; i<4; i++){ code += randomChar(); } int width = 70; int height = 25; BufferedImage bi = new BufferedImage(width,height,BufferedImage.TYPE_3BYTE_BGR); Font font = new Font("Times New Roman",Font.PLAIN,20); Graphics2D g = bi.createGraphics(); g.setFont(font); Color color = new Color(66,2,82); g.setColor(color); g.setBackground(new Color(226,226,240)); g.clearRect(0, 0, width, height); FontRenderContext context = g.getFontRenderContext(); Rectangle2D bounds = font.getStringBounds(code, context); double x = (width - bounds.getWidth()) / 2; double y = (height - bounds.getHeight()) / 2; double ascent = bounds.getY(); double baseY = y - ascent; g.drawString(code, (int)x, (int)baseY); g.dispose(); try { ImageIO.write(bi, "jpg", output); } catch (IOException e) { //e.printStackTrace(); } return code; } private char randomChar(){ Random r = new Random(); String s = "ABCDEFGHJKLMNPRSTUVWXYZ0123456789"; return s.charAt(r.nextInt(s.length())); } }