本文实例为大家分享了C语言实现简单的扫雷小游戏的具体代码，供大家参考，具体内容如下
首先来规划一下扫雷游戏实现的几个步骤：
初始化棋盘：二维数组的遍历及赋值
为了后续代码的简洁方便，我们用'0'来初始化
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void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
int i = 0;
int j = 0;
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
board[i][j] = set;
}
}
}
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布置雷的信息：应用随机函数进行赋值
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void SetMine(char mine[ROWS][COLS], int row, int col)
{
int count = EASY_COUNT;
while (count)
{
int x = rand() % row + 1;
int y = rand() % col + 1;
if (mine[x][y] == '0')
{
mine[x][y] = '1';
count--;
}
}
}
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排查雷：
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void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x = 0;
int y = 0;
int win = 0;
while (win<row*col- EASY_COUNT)
{
printf("请输入要排查的坐标->");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
{
if (mine[x][y] == '1')
{
printf("很遗憾你被炸死了\n");
DisplayBoard(mine, row, col);
break;
}
else
{
//计算x,y坐标周围有几个雷
int n=get_mine_count(mine, x, y);
show[x][y] = n + '0';
DisplayBoard(show, row, col);
win++;
}
}
else
printf("输入坐标错误，请重新输入\n");
}
if (win == row * col - EASY_COUNT)
{
printf("恭喜你，排雷成功\n");
DisplayBoard(mine, row, col);
}
}
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下面是游戏实现的完整代码，依旧是分为了3个版块，为了更好的管理代码，提高代码的可读性和可移植性
game2.h
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#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define ROW 9
#define COL 9
#define EASY_COUNT 10
#define ROWS ROW+2
#define COLS COL+2
//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
//打印棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col);
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);
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game2.c
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#include "game2.h"
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
int i = 0;
int j = 0;
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
board[i][j] = set;
}
}
}
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i <= col; i++)
{
printf("%d ", i);
}
printf("\n");
for (i = 1; i <= row; i++)
{
printf("%d ", i);
for (j = 1; j <= col; j++)
{
printf("%c ", board[i][j]);
}
printf("\n");
}
}
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{
int count = EASY_COUNT;
while (count)
{
int x = rand() % row + 1;
int y = rand() % col + 1;
if (mine[x][y] == '0')
{
mine[x][y] = '1';
count--;
}
}
}
static int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
return mine[x - 1][y] +
mine[x - 1][y - 1] +
mine[x][y - 1] +
mine[x + 1][y] +
mine[x + 1][y + 1] +
mine[x][y + 1] +
mine[x - 1][y + 1]+
mine[x+1][y-1]-8*'0';
}
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x = 0;
int y = 0;
int win = 0;
while (win<row*col- EASY_COUNT)
{
printf("请输入要排查的坐标->");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
{
if (mine[x][y] == '1')
{
printf("很遗憾你被炸死了\n");
DisplayBoard(mine, row, col);
break;
}
else
{
//计算x,y坐标周围有几个雷
int n=get_mine_count(mine, x, y);
show[x][y] = n + '0';
DisplayBoard(show, row, col);
win++;
}
}
else
printf("输入坐标错误，请重新输入\n");
}
if (win == row * col - EASY_COUNT)
{
printf("恭喜你，排雷成功\n");
DisplayBoard(mine, row, col);
}
}
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test.c
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#include "game2.h"
void menu()
{
printf("**************************\n");
printf("******* 1.play *******\n");
printf("******* 0.exit *******\n");
printf("**************************\n");
}
void game()
{
//创建数组
char mine[ROWS][COLS] = { 0 };//存放布置好的雷的信息
char show[ROWS][COLS] = { 0 };//存放排查出的雷的信息
//初始化mine数组全部为‘0'
InitBoard(mine, ROWS, COLS, '0');
//初始化show数组全部为‘0'
InitBoard(show, ROWS, COLS, '*');
//打印棋盘
//DisplayBoard(mine, ROW, COL);
//布置雷
SetMine(mine, ROW, COL);
DisplayBoard(show, ROW, COL);
//DisplayBoard(mine, ROW, COL);
//排查雷
FindMine(mine, show, ROW, COL);
}
void test()
{
int input = 0;
srand((unsigned int)time(NULL));
do
{
menu();
printf("请选择->");
scanf("%d", &input);
switch (input)
{
case 1:
game();
break;
case 0:
printf("退出游戏\n");
break;
default:
printf("选择错误\n");
break;
}
} while (input);
}
int main()
{
test();
return 0;
}
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以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/weixin_54175406/article/details/121442177