i have following xml file as input ....
我有下面的xml文件作为输入....
<?xml version="1.0" encoding="ISO-8859-1"?>
<T0020
xsi:schemaLocation="http://www.safersys.org/namespaces/T0020V1 T0020V1.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.safersys.org/namespaces/T0020V1">
<INTERFACE>
<NAME>SAFER</NAME>
<VERSION>04.02</VERSION>
</INTERFACE>
<TRANSACTION>
<VERSION>01.00</VERSION>
<OPERATION>REPLACE</OPERATION>
<DATE_TIME>2009-09-01T00:00:00</DATE_TIME>
<TZ>CT</TZ>
</TRANSACTION>
<IRP_ACCOUNT>
<IRP_CARRIER_ID_NUMBER>274845</IRP_CARRIER_ID_NUMBER>
<IRP_BASE_COUNTRY>US</IRP_BASE_COUNTRY>
<IRP_BASE_STATE>AR</IRP_BASE_STATE>
<IRP_ACCOUNT_NUMBER>55002</IRP_ACCOUNT_NUMBER>
<IRP_ACCOUNT_TYPE>I</IRP_ACCOUNT_TYPE>
<IRP_STATUS_CODE>100</IRP_STATUS_CODE>
<IRP_STATUS_DATE>2007-11-06</IRP_STATUS_DATE>
<IRP_UPDATE_DATE>2009-08-03</IRP_UPDATE_DATE>
<IRP_NAME>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>A P SUPPLY CO</NAME>
<IRP_ADDRESS>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
<STREET_LINE_1>1400 N OATS</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>71854</ZIP_CODE>
<COUNTY>MILLER</COUNTY>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
<IRP_ADDRESS>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
<STREET_LINE_1>P O BOX 1927</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>75504</ZIP_CODE>
<COUNTY/>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
</IRP_NAME>
</IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
and i want to take this xml file and split it into multiple files through java code like this ...
我想把这个xml文件通过这样的java代码分割成多个文件……
File1.xml
File1.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
File2.xml
File2.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
File3.xml
File3.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
and many more xml file .Each xml file contain maximum 10 or 15 IRP_ACCOUNT.
每个xml文件包含最多10或15个IRP_ACCOUNT。
Can somebody please help me ?
有人能帮我吗?
1 个解决方案
#1
16
Quick and dirty:
快速和肮脏的:
public class XmlSplit {
public static void main(String [] args) throws Exception {
File input = new File("input.xml");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
Document doc = dbf.newDocumentBuilder().parse(input);
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodes = (NodeList) xpath.evaluate("//T0020/IRP_ACCOUNT", doc, XPathConstants.NODESET);
int itemsPerFile = 5;
int fileNumber = 0;
Document currentDoc = dbf.newDocumentBuilder().newDocument();
Node rootNode = currentDoc.createElement("T0020");
File currentFile = new File(fileNumber+".xml");
for (int i=1; i <= nodes.getLength(); i++) {
Node imported = currentDoc.importNode(nodes.item(i-1), true);
rootNode.appendChild(imported);
if (i % itemsPerFile == 0) {
writeToFile(rootNode, currentFile);
rootNode = currentDoc.createElement("T0020");
currentFile = new File((++fileNumber)+".xml");
}
}
writeToFile(rootNode, currentFile);
}
private static void writeToFile(Node node, File file) throws Exception {
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.transform(new DOMSource(node), new StreamResult(new FileWriter(file)));
}
}
#1
16
Quick and dirty:
快速和肮脏的:
public class XmlSplit {
public static void main(String [] args) throws Exception {
File input = new File("input.xml");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
Document doc = dbf.newDocumentBuilder().parse(input);
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodes = (NodeList) xpath.evaluate("//T0020/IRP_ACCOUNT", doc, XPathConstants.NODESET);
int itemsPerFile = 5;
int fileNumber = 0;
Document currentDoc = dbf.newDocumentBuilder().newDocument();
Node rootNode = currentDoc.createElement("T0020");
File currentFile = new File(fileNumber+".xml");
for (int i=1; i <= nodes.getLength(); i++) {
Node imported = currentDoc.importNode(nodes.item(i-1), true);
rootNode.appendChild(imported);
if (i % itemsPerFile == 0) {
writeToFile(rootNode, currentFile);
rootNode = currentDoc.createElement("T0020");
currentFile = new File((++fileNumber)+".xml");
}
}
writeToFile(rootNode, currentFile);
}
private static void writeToFile(Node node, File file) throws Exception {
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.transform(new DOMSource(node), new StreamResult(new FileWriter(file)));
}
}