将1D数组索引转换为2D数组索引

I have 2 arrays. I want to convert the index of the first array to the second. Is there a better way to do it than what I have below?

我有2个阵列。我想将第一个数组的索引转换为第二个数组。有没有比我下面更好的方法呢？

Array array1[9];
Array array2[3][3];

// Index is the index of the 1D array
public Point convert1Dto2D(int index)
{
        Point p = new Point();

        switch (index) {
            case 0:
                p.x = 0;
                p.y = 0;
                break;
            case 1:
                p.x = 0;
                p.y = 1;
                break;
            case 2:
                p.x = 0;
                p.y = 2;
                break;
            case 3:
                p.x = 1;
                p.y = 0;
                break;
            case 4:
                p.x = 1;
                p.y = 1;
                break;
            case 5:
                p.x = 1;
                p.y = 2;
                break;
            case 6:
                p.x = 2;
                p.y = 0;
                break;
            case 7:
                p.x = 2;
                p.y = 1;
                break;
            case 8:
                p.x = 2;
                p.y = 2;
                break;
        }

return p;
}

3 个解决方案

#1

p.x = index / 3;
p.y = index % 3;

#2

You can do this mathematically using modulus and integer division, given your second array is a 3x3 array the following will do.

您可以使用模数和整数除法进行数学运算，假设您的第二个数组是3x3数组，以下将执行此操作。

p.y = index % 3;
p.x = index / 3;

#3

I assume your running that code in a loop? If so

我假设您在循环中运行该代码？如果是这样

IEnumerable<Point> DoStuff(int length, int step) {
    for (int i = 0; i < length; i++)
        yield return new Point(i/step, i%step);
}

Call it

叫它

foreach (var element in DoStuff(9, 3))
    {
        Console.WriteLine(element.X);
        Console.WriteLine(element.Y);
    }

#1

p.x = index / 3;
p.y = index % 3;

#2