Self Numbers 分类: POJ 2015-06-12 20:07 14人阅读 评论(0) 收藏

时间:2024-01-04 15:42:38
Self Numbers
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 22101   Accepted: 12429

Description

In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called self-numbers. For any positive integer n, define d(n) to be n plus the sum of the digits of n. (The d stands for digitadition, a term coined by
Kaprekar.) For example, d(75) = 75 + 7 + 5 = 87. Given any positive integer n as a starting point, you can construct the infinite increasing sequence of integers n, d(n), d(d(n)), d(d(d(n))), .... For example, if you start with 33, the next number is 33 +
3 + 3 = 39, the next is 39 + 3 + 9 = 51, the next is 51 + 5 + 1 = 57, and so you generate the sequence




33, 39, 51, 57, 69, 84, 96, 111, 114, 120, 123, 129, 141, ...

The number n is called a generator of d(n). In the sequence above, 33 is a generator of 39, 39 is a generator of 51, 51 is a generator of 57, and so on. Some numbers have more than one generator: for example, 101 has two generators, 91 and 100. A number with
no generators is a self-number. There are thirteen self-numbers less than 100: 1, 3, 5, 7, 9, 20, 31, 42, 53, 64, 75, 86, and 97.



Input

No input for this problem.

Output

Write a program to output all positive self-numbers less than 10000 in increasing order, one per line.

Sample Input


Sample Output

1
3
5
7
9
20
31
42
53
64
|
| <-- a lot more numbers
|
9903
9914
9925
9927
9938
9949
9960
9971
9982
9993
就是筛选出10000以内的Self Numbers,类似素数筛
#include <cstdio>
#include <string.h>
#include <cmath>
#include <iostream>
#include <algorithm>
#define WW freopen("output.txt","w",stdout)
using namespace std;
const int Max=10000;
bool vis[Max];
int main()
{
memset(vis,false,sizeof(vis));
for(int i=1; i<Max; i++)
{
if(!vis[i])
{
int ans=i;
while(ans<Max)
{
int ant=ans;
while(ans)
{
ant+=(ans%10);
ans/=10;
}
ans=ant;
if(!vis[ans])
vis[ans]=true;
else
{
break;
}
}
}
}
for(int i=1; i<Max; i++)
{
if(vis[i])
continue;
printf("%d\n",i);
}
return 0;
}

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