题目链接:
Desert
Time Limit: 2000/1000 MS (Java/Others)
Memory Limit: 65535/32768 K (Java/Others)
Problem Description
A tourist gets lost in the desert with n liters of water. He drinks positive integer units of water each day.
Write a program to calculate how many different ways the tourist can drink up the water.
Input
The first line contains the number of test cases T(T≤10).
Next T lines contain the number n(1≤n≤1000000) for each test case.
Next T lines contain the number n(1≤n≤1000000) for each test case.
Output
Output consists of T lines.
Each line contains the binary number which represents number of different ways to finish up the water specified in the test case.
Each line contains the binary number which represents number of different ways to finish up the water specified in the test case.
Sample Input
1
3
Sample Output
100
题意:
n是多少个不同序列的和?
思路:
可以发现是2^(n-1)种;
AC代码:
#include <bits/stdc++.h>
/*
#include <iostream>
#include <queue>
#include <cmath>
#include <map>
#include <cstring>
#include <algorithm>
#include <cstdio>
*/
using namespace std;
#define Riep(n) for(int i=1;i<=n;i++)
#define Riop(n) for(int i=0;i<n;i++)
#define Rjep(n) for(int j=1;j<=n;j++)
#define Rjop(n) for(int j=0;j<n;j++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef long long LL;
const LL mod=1e9+;
const double PI=acos(-1.0);
const LL inf=1e18;
const int N=1e6+;
int n,q;
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
n--;
printf("");
while(n--)printf("");
printf("\n");
}
return ;
}