题意:判断链表是否有环。
分析:快慢指针。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
ListNode* fast = head;
ListNode* slow = head;
while(fast && fast -> next){
fast = fast -> next -> next;
slow = slow -> next;
if(fast == slow) return true;
}
return false;
}
};