CodeCombat森林关卡Python代码

时间:2023-12-29 19:10:26

地牢关卡过完,接下来是边缘的森林!

1,森林保卫战

hero.moveUp()
hero.buildXY("fence", 40, 52)
hero.moveDown()
hero.moveDown()
hero.buildXY("fence", 40, 20)

2,羊肠小道

# It's the first point of the path.
hero.moveXY(36, 59)
# Move at the next points of the path.
hero.moveXY(37, 13)
# Build a fence to stop the ogre.
hero.moveXY(79,18)
hero.moveXY(73,61)
hero.moveXY(79,18)

3,丛林里的隔间

hero.moveXY(19, 33)
enemy = hero.findNearestEnemy()
# 条件判断式将会检查该变数是否参考到一个ogre
if enemy:
hero.attack(enemy)
hero.attack(enemy) hero.moveXY(49, 51)
enemy = hero.findNearestEnemy()
if enemy:
# 在这里撰写攻击敌人指令
hero.attack(enemy)
hero.attack(enemy)
# pass没有特别的意思,只是用来协助结束条件判断式,写不写都可以
pass hero.moveXY(58, 14)
enemy = hero.findNearestEnemy()
# 使用条件判断式来确认敌人是否存在
if enemy:
# 如果敌人存在就攻击他
hero.attack(enemy)
hero.attack(enemy)

4,if-stravaganza

while True:
enemy = hero.findNearestEnemy()
# 使用一个 “if” 语句去检查是否有敌人存在:
if enemy:
# 攻击敌人如果它存在的话
hero.attack(enemy)
hero.attack(enemy)

5,背靠背

while True:
enemy = hero.findNearestEnemy()
if enemy:
# 亦或主动出击...
hero.attack(enemy)
hero.attack(enemy)
else:
# 亦或回到你的阵地防守。
hero.say(" 我看不到敌人")
hero.moveXY(40, 34)
pass

6,森林劈裂者

hero.moveXY(23, 23)
while True:
enemy = hero.findNearestEnemy()
if hero.isReady("cleave"):
# “Cleave”掉敌人!
hero.cleave(enemy)
pass
else:
# 否则(如果“cleave”还没准备好),就用你的普通攻击
hero.attack(enemy)
pass

7,边远地区的对峙

while True:
# 使用 ‘isReady’ 中的一个 “if-statement” 的语句来检查 “cleave”
if hero.isReady("cleave"):
# 劈斩!
enemy = hero.findNearestEnemy()
hero.cleave(enemy)
# 或者,如果 cleave 还没准备好的话:
else:
# 说一点什么来吓走曼切堪食人魔
hero.say(" 快滚吧!刀剑无眼 ! ")
pass

8,测距仪

enemy1 = "Gort"
distance1 = hero.distanceTo(enemy1)
hero.say(distance1)
enemy2 = "Smasher"
distance2 = hero.distanceTo(enemy2)
# 将distance2变数作为参数,传入say()方法
hero.say(distance2)
# 测量并说出剩余敌人与英雄间的距离
# 不要向你的友军进行射击!
enemy3 = "Charles"
enemy4 = "Gorgnub"
distance4 = hero.distanceTo(enemy4)
hero.say(distance4)

9,保护农民

while True:
enemy = hero.findNearestEnemy()
distance = hero.distanceTo(enemy)
if distance < 10:
# 如果他们与农民太近,就攻击他们
hero.attack(enemy)
pass
# 否则的话,呆在农民旁边!
hero.moveXY(40, 37)

10,疯狂的食人魔

# 地上另一个让英雄打开的宝箱!
# 攻击宝箱以打开它
# 有些食人魔可不会呆呆地站着挨打!
# 当食人魔离你太近时,你得学着保护你自己
while True:
enemy = hero.findNearestEnemy()
distance = hero.distanceTo(enemy)
if hero.isReady("cleave"):
# 首先,定期使用旋风斩(cleave)当技能就绪的时候:
hero.cleave(enemy)
pass
elif distance < 5:
# 攻击靠近并离你最近的食人魔
hero.attack(enemy)
pass
else:
# 否则,试着打破宝箱看看:
hero.attack("Chest")
pass

11,跃火林中

# 在这关,别碰恶魔石!往其他方向移动避开它们!
while True:
evilstone = hero.findNearestItem()
if evilstone:
pos = evilstone.pos
if pos.x == 34:
# 如果恶魔石在左边,走到右边。
hero.moveXY(46, 22)
pass
else:
# 如果恶魔石在右边,走到左边。
hero.moveXY(34, 22)
pass
else:
# If there's no evilstone, go to the middle.
hero.moveXY(40, 22)
pass

12,Village Rover

# This defines a function called findAndAttackEnemy
def findAndAttackEnemy():
enemy = hero.findNearestEnemy()
if enemy:
hero.attack(enemy) # This code is not part of the function.
while True:
# Now you can patrol the village using findAndAttackEnemy
hero.moveXY(35, 34)
findAndAttackEnemy() # Now move to the right entrance.
hero.moveXY(60, 31)
# Use findAndAttackEnemy
findAndAttackEnemy()

13,Backwoods Fork

# This function has a parameter.
# 参数是一种给函数传递信息的方式。
def checkAndAttack(target):
# The 'target' parameter is just a variable!
# 它包含了函数调用时的参数。
if target:
hero.attack(target)
hero.moveXY(43, 34) while True:
hero.moveXY(58, 52)
topEnemy = hero.findNearestEnemy()
checkAndAttack(topEnemy) # 移动到底部的X标记处。
hero.moveXY(58, 16)
# 创建名为 bottomEnemy 的变量,寻找最近敌人。
bottomEnemy = hero.findNearestEnemy()
# 使用 checkAndAttack 函数,并包括 bottomEnemy 变量。
checkAndAttack(bottomEnemy)

14,Leave it to Cleaver

# This shows how to define a function called cleaveWhenClose
# The function defines a parameter called target
def cleaveWhenClose(target):
if hero.distanceTo(target) < 5:
pass
# Put your attack code here
# If cleave is ready, then cleave target
hero.cleave(enemy)
# else, just attack target!
hero.attack(enemy) # This code is not part of the function.
while True:
enemy = hero.findNearestEnemy()
if enemy:
# Note that inside cleaveWhenClose, we refer to the enemy as target.
cleaveWhenClose(enemy)

15,友人和敌人

# 农民和士兵聚集在森林。
# 命令农民战斗,苦工远离! while True:
friend = hero.findNearestFriend()
if friend:
hero.say("To battle, " + friend.id + "!")
# 寻找最近的敌人,然后让他们滚蛋
enemy = hero.findNearestEnemy()
if enemy:
hero.say("Scram," + enemy.id + "!")

16,巫师之门

# Move to Laszlo and get his secret number.
hero.moveXY(30, 13)
las = hero.findNearestFriend().getSecret() # 向 Laszlo 的数字中加7就能得到 Erzsebet的号码
# Move to Erzsebet and say her magic number.
erz = las + 7
hero.moveXY(17, 26)
hero.say(erz) # 将 Erzsebet 的数字除以 4 得到 Simoyi 的数字。
# Go to Simonyi and tell him his number.
sim = erz / 4
hero.moveXY(30, 39)
hero.say(sim) # 将 Simonyi 的数字乘以 Laszlo 的数字得到 Agata 的数字。
# Go to Agata and tell her her number.
Aga = sim * las
hero.moveXY(43, 26)
hero.say(Aga)

17,金币屑

# 跟随硬币的轨迹来到红色 X 标记的出口

while True:
# 这能找到最近的敌人。
item = hero.findNearestItem()
if item:
# 这将物品的 pos,就是坐标,存储在变量中。
itemPosition = item.pos
# 将物品的 X 和 Y 坐标放进变量。
itemX = itemPosition.x
itemY = itemPosition.y
# Now, use moveXY to move to itemX and itemY:
hero.moveXY(itemX, itemY)

18,Blind Distance

# 你的任务是告诉他兽人的距离。

# 这个函数寻找最近的敌人,并返回距离。
# If there is no enemy, the function returns 0.
def nearestEnemyDistance():
enemy = hero.findNearestEnemy()
result = 0
if enemy:
result = hero.distanceTo(enemy)
return result while True:
# Call nearestEnemyDistance() and
# save the result in the variable enemyDistance.
enemyDistance = nearestEnemyDistance()
# If the enemyDistance is greater than 0:
if enemyDistance:
# Say the value of enemyDistance variable.
hero.say(enemyDistance)

可选关卡1:竞技场

# 在决斗中击败敌人的英雄!
while True:
# 在一个循环中找到并攻击敌人
# 当你完成的时候,提交到多人天梯系统中!
enemy = hero.findNearestEnemy()
hero.attack(enemy)
if len(hero.findNearestEnemy()) > 5:
hero.shield()
else:
hero.attack(enemy)