正则表达式从歌曲名称中删除曲目编号？

I have a ListView that display song names and artists. Sometimes, the song names contain the track number and a separator with some in this format

我有一个ListView,显示歌曲名称和艺术家。有时,歌曲名称包含曲目编号和分隔符,其中包含一些格式

13 - J. Cole - Best Friend

and others like this

和其他人一样

13 - Beautiful People

After some digging around I found that the best way to go about this is to define a regex pattern that will remove any unnecessary characters in the string. Cool. I've looked at other SO questions on a similar topic here and a couple blog posts but still no luck.

经过一番挖掘后,我发现最好的方法是定义一个正则表达式模式,它将删除字符串中的任何不必要的字符。凉。我在这里查看了类似主题的其他SO问题以及一些博客文章,但仍然没有运气。

This my first time dealing with regular expressions and I find it quite useful, just trying to wrap my head around coming up with efficient/useful patterns.

这是我第一次处理正则表达式,我发现它非常有用,只是试图提出有效/有用的模式。

Here's what I need to remove from the string if it is a match

如果是匹配的话,这就是我需要从字符串中删除的内容

The track number
The "-" or whatever separator character that follows it
The artist name and the "-" that follows that(Each artist name is listed below the   song, so it would be redundant)

Any help on this would be greatly appreciated as usual guys, thanks!

任何有关这方面的帮助都会像往常一样非常感谢,谢谢!

Edit: The same output that I would like is something like this, with just the song names. No track numbers, and if applicable; no artist names following the "-"

编辑:我想要的相同输出是这样的,只有歌曲名称。没有曲目编号,如果适用的话; “ - ”后面没有艺术家姓名

Beautiful People
Angel of Mine
Human Nature

3 个解决方案

#1

Here's a possible regex you could use:

这是一个可以使用的正则表达式:

name.replaceFirst("^\\d+\\.?\\s*-(?:.*?-)?\\s*", "")

This takes out:

这取出:

digits at the front

前面的数字

optionally followed by a dot

可选地后跟一个点

optionally spaces
a hyphen
if a further hyphen is found, then everything up to that

如果找到另一个连字符,那么一切都是如此

optionally spaces

#2

A piece of code will be better to give you a hint:

一段代码会更好地给你一个提示:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {

    public static void main(String[] args) {

        String[] songNames = {
            "1 - my awesome artist - go beyond",
            "2 - such is life",
            "My awesome song"
        };



        Pattern trackNumberPattern = Pattern.compile("^ *\\d+ *- *");
        Pattern artistPattern = Pattern.compile(" *- *[^-]+ *- *");

        Matcher matcher;

        for(String song: songNames) {

            matcher = trackNumberPattern.matcher(song);
            if(matcher.find()) {
                song = matcher.replaceFirst("");
            }

            matcher = artistPattern.matcher(song);
            if(matcher.find()) {
                song = matcher.replaceFirst("");
            }

            System.out.println(">>> " + song);

        }
    }

}

You can find the doc to write regex in java here: http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html

你可以在这里找到用java编写正则表达式的文档:http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html

DISCLAIMER: This won't work properly if some of the song names or artist names contain dashes (-), etc...

免责声明:如果某些歌曲名称或艺术家名称包含破折号( - )等,这将无法正常工作......

#3

You can use this regex (a little bit radical):

你可以使用这个正则表达式(有点激进):

^\\d*+\\W*+\\b(?>[^-]++-\\s++(?=\w))?

and replace it by nothing.

并取而代之的是什么。

this will destroy all digits followed by non-word characters at the begining, and the interpret name if it is present

这将破坏所有数字,后跟开头的非单词字符,以及解释名称(如果存在)

#1