<script>
(使用正则表达式和JavaScript)
$('.time_info').html()
</script>
3 个解决方案
#1
var reg=/-|(?::\d+$)/g;
var str='2016-08-09 07:04:56';
str=str.replace(reg,'');
alert(str);
var str='2016-08-09 07:04:56';
str=str.replace(reg,'');
alert(str);
#2
方法1(不管不顾替换法):
方法2(整体提取拼装法):
var ele = document.querySelector(".time_info");
ele.innerHTML = ele.innerHTML.replace(/-/g,"");
方法2(整体提取拼装法):
var str = "2016-8-9 7:04:56.540";
var reg = /^(\d{4})-(\d{1,2})-(\d{1,2})(\s|T)(\d{1,2})(:(\d{1,2}))?(:(\d{1,2}))?(\.(\d{1,3}))?$/g;
arr = reg.exec(str);
var result = "我在今年" + arr[1] + "年" + arr[2] + "月" + arr[3] + "日" + arr[5] + ":" + arr[7] + ":" + arr[9] + "又" + arr[11] + "毫秒,发了一个帖子";
document.querySelector(".time_info").innerHTML = result ;
#3
一楼的方法可行,和我的思路一致
#1
var reg=/-|(?::\d+$)/g;
var str='2016-08-09 07:04:56';
str=str.replace(reg,'');
alert(str);
var str='2016-08-09 07:04:56';
str=str.replace(reg,'');
alert(str);
#2
方法1(不管不顾替换法):
方法2(整体提取拼装法):
var ele = document.querySelector(".time_info");
ele.innerHTML = ele.innerHTML.replace(/-/g,"");
方法2(整体提取拼装法):
var str = "2016-8-9 7:04:56.540";
var reg = /^(\d{4})-(\d{1,2})-(\d{1,2})(\s|T)(\d{1,2})(:(\d{1,2}))?(:(\d{1,2}))?(\.(\d{1,3}))?$/g;
arr = reg.exec(str);
var result = "我在今年" + arr[1] + "年" + arr[2] + "月" + arr[3] + "日" + arr[5] + ":" + arr[7] + ":" + arr[9] + "又" + arr[11] + "毫秒,发了一个帖子";
document.querySelector(".time_info").innerHTML = result ;
#3
一楼的方法可行,和我的思路一致